In one of his earlier vids he said that the current throughout the circuit is constant but in this video he said that the current are different at diferent places? wouldn't there be a "build-up" of electrons if there different currents????
0:38 - Sal: "4Ω, 8Ω, 16Ω..." - Me: "Powers of 2, next should be 32Ω" - Sal: "I am actually making numbers up on the fly: 16Ω (again)" - Me: "FFFFFUUUUUUUUUUUU..."
You should do one circuit w/ 3 identical resistors in parallel and then tell us what happens to the voltage, the current, and the brightness of the two lightbulbs left when you take one of them off the circuit.
@khanacademy You're videos are great! However, I would like to request that you do more videos for electrical engineering, covering further topics such as inductors, capacitors, RLC circuits, etc... That would be great if possible. Thanks again.
"1/4 = 4/16 you messed up a little on the second 1/4" @ bentodd1
"OK GUYS JUST CALM DOWN, the 1/16 he wrote looks like 1/4...just don't get confused...in the diagram he drew there was two 16 ohm resistors so Rt does equal 2 ohms." @sh3rl0ck999
OK GUYS JUST CALM DOWN, the 1/16 he wrote looks like 1/4...just don't get confused...in the diagram he drew there was two 16 ohm resistors so Rt does equal 2 ohms.
Wait I'm pretty sure he made an error when adding up the top resistances. I think his fractions are incorrect because isn't supposed to be (4+2+1+4)/16? The last number is supposed to be 4 not 1.
@IPMountainDew I don't think finding each value of the resistance is possible only possible values for each that would make the equation true. Since there would be a huge amount of possible values It would qualify for as a problem of "Great hair density and length" ;)
Finding voltage given all resistance values and current is very possible(simple) however.
Do students in US schools actually understands all these concepts? That is can they construct a circuit themselves? I thought US physics education is not strong.
@comecra85 These are very basic concepts with very, VERY basic math. Don't believe everything you see on the internet and TV about people in the US. There is nothing remotely difficult about this.
check out Dunwoody College of Technology's on series/parallel combination circuits (by Eeris Fritz) for extra help which offers a two step method that is easy to follow.
Also I think it'd be nice if you did some optics videos, wave phenomena, diffraction gratings, double/single slit interference, thin films, resolution!
I don't get this, you say that the voltage is the same at any point in the circuit, but in this problem i have the V is 100v, and she says that V3 is 6v. I thought it was the same no matter where you are on the circuit
@max1916251080 In the parallel portion of the circuit the voltage is constant across each "branch". But if there are portions in series then there are voltage drops across these series-resistors sections. So there are voltage drops across these collection of "branches"
Thanks for all the video's so far, they have helped me a lot with my studies!
But im still left with some questions about circuits; what will happen if you add mutiple U's (dunno the word :-) ) intro the circuit? What will happen with the flow of electrons? And what will happen if you put them in parallel?
Thanks for your clear video's! Looking forward to the new video's!
I disagree with the comment below to some extent, only because some stuff you draw I can't read but you say what it is out loud as you are drawing it so I know what it is.
These videos by the way are awesome, thanks for putting them up!
i'd suggest . . . no, i would plead that you re-rercord these chapters AFTER you have written a script and rehearsed. if you listen to the presentation with your eyes closed, and/or watch without volume, i think you might agree. some one with no basic concept could easily get lost and give up in frustration. the information is all there however the dialogue wanders occaisionaly and the sketches and equations can be difficult to to take notes, for later review. thanks sc
the voltage at each resistor is just the voltage drop. to find this you first have to know the current going through all the resistors in the series configuration shown at the end, this is 8 amps, then you multiply the total current by each resistance. The current through each resistor in series is the same for the equivalent circuit, and in parallel resistors the voltage across each resistor is the same so you can use ohm's law to find current.
There isn't a math error. (1/Rt)=(1/4)+(1/8)+(1/16)+(1/16). The way its written the last (1/16) looks like (1/4) but its really (1/ the resister on the bottom of the group hes evaluating.
wow great video, although I don't really have problems understanding electronics in my physics class but this video really does give an intuitive feel. and I am not just saying that!
QUESTION:
In one of his earlier vids he said that the current throughout the circuit is constant but in this video he said that the current are different at diferent places? wouldn't there be a "build-up" of electrons if there different currents????
hockeymo 1 day ago in playlist Physics
0:38 - Sal: "4Ω, 8Ω, 16Ω..." - Me: "Powers of 2, next should be 32Ω" - Sal: "I am actually making numbers up on the fly: 16Ω (again)" - Me: "FFFFFUUUUUUUUUUUU..."
cowzrule101 1 month ago
what do u look like?
shenoycdx 1 month ago
@shenoycdx Theres a video of him at a conference or something with Bill Gates on his channel
chillerized 3 weeks ago
You should do one circuit w/ 3 identical resistors in parallel and then tell us what happens to the voltage, the current, and the brightness of the two lightbulbs left when you take one of them off the circuit.
pseudorealista 2 months ago
@khanacademy You're videos are great! However, I would like to request that you do more videos for electrical engineering, covering further topics such as inductors, capacitors, RLC circuits, etc... That would be great if possible. Thanks again.
yamenhawit 3 months ago 2
Is there anything you DON'T know? haha thanks though.
ChrisTheDIYguy 3 months ago 2
can someone please tell me if theres a potential dividers video?
slyfox551 4 months ago in playlist Physics
Thank you for these videos... Your videos are the most helpful I've seen online.
WVENGINEERING 4 months ago
question
could we have simplified all the resistors at once
benja303 5 months ago
This has been flagged as spam show
"1/4 = 4/16 you messed up a little on the second 1/4" @ bentodd1
"OK GUYS JUST CALM DOWN, the 1/16 he wrote looks like 1/4...just don't get confused...in the diagram he drew there was two 16 ohm resistors so Rt does equal 2 ohms." @sh3rl0ck999
lmao which one needs to calm down??
benja303 5 months ago
OK GUYS JUST CALM DOWN, the 1/16 he wrote looks like 1/4...just don't get confused...in the diagram he drew there was two 16 ohm resistors so Rt does equal 2 ohms.
sh3rl0ck999 5 months ago 2
1/4 = 4/16 you messed up a little on the second 1/4
bentodd1 6 months ago 3
Thnks u r gr8
TheMichaeljohnny 6 months ago
Wait I'm pretty sure he made an error when adding up the top resistances. I think his fractions are incorrect because isn't supposed to be (4+2+1+4)/16? The last number is supposed to be 4 not 1.
fighter91 6 months ago
thank you!!
kokaiini 6 months ago
I love u SIR..... for all of these great vedios......!!!! thanxxxxxxxxx alot
hazara67 8 months ago
thanks man. i have a test on this really soon
609197 9 months ago
@609197 hey i've got a test on it too! lolz...to be specific..on wednesday =P
DaniellaRox123 9 months ago
I <3 you
DMerk2012 9 months ago
Mmm loved me a bitta hairy circuit problems.
griftorifto2 9 months ago
THANK YOU !
FLAMERNECRO 10 months ago
great tutorial..
ishan0833 10 months ago
Ok sweet vid but what if we try to find the voltage, or each value of the resistance (not given)
IPMountainDew 10 months ago
@IPMountainDew I don't think finding each value of the resistance is possible only possible values for each that would make the equation true. Since there would be a huge amount of possible values It would qualify for as a problem of "Great hair density and length" ;)
Finding voltage given all resistance values and current is very possible(simple) however.
griftorifto2 9 months ago
At the start I actually said, "This guy is a lunatic!" Great video :D
metalmaniac767 10 months ago
good job resolving it, i dont realy like hairy stuff
NinjaMotion 10 months ago
You shaved that problem.
animefreak619240 11 months ago 3
at 5:55 don't you mean there are two resistors left in series, not parallel?
gbmack2000 1 year ago
@gbmack2000 He corrects himself shortly afterward.
TheBrigadeCheif 10 months ago
Sal could you please make lessons about Wheatstone bridges, potientiometry and kirchhoffs Law. Thankyou
alifawad1994 1 year ago
this also help me itunes.apple.com/us/app/star2delta/id417605678?mt=8
richimf 1 year ago
Why can't you teach my physics class!? Thank you so much!
jessiemsy 1 year ago
Reli helpful on my study !thank you very much!
MsRoseapple 1 year ago
Hairy?
spysr 1 year ago
These videos are spectacular! I would love to hear you explain the Wheatstone Bridge if you have the time!
ag1293 1 year ago
good work (Y)
TheUnchainedBeast 1 year ago
I watched this after my circuits test... I would totally ace any question now = ) thanks!
Mcplumpyboy 1 year ago
Do students in US schools actually understands all these concepts? That is can they construct a circuit themselves? I thought US physics education is not strong.
comecra85 1 year ago
@comecra85 These are very basic concepts with very, VERY basic math. Don't believe everything you see on the internet and TV about people in the US. There is nothing remotely difficult about this.
jffersontube 1 year ago
@comecra85 Have you ever heard of Nasa?
nickrohn93 11 months ago
@comecra85 Or MIT, Harvard, Princeton, Standford, Yale...
nickrohn93 11 months ago
check out Dunwoody College of Technology's on series/parallel combination circuits (by Eeris Fritz) for extra help which offers a two step method that is easy to follow.
eefritz 1 year ago
MATHEMATICS
DRAN4612 1 year ago
haha thanks fo all the videos! you teach better than my teacher. really;))
poshablyposh 1 year ago
What is the meaning of a hairy problem? Btw, very good explanation.
boeing747200lr 1 year ago
"alot less hairy" lol cos you gave it a good shave :)
robo2000nitro 1 year ago
Also I think it'd be nice if you did some optics videos, wave phenomena, diffraction gratings, double/single slit interference, thin films, resolution!
SecretAsianMan7 1 year ago
Yes RL, RC, and LC circuit videos would be helpful! Also Maxwells laws, Biot-Savart law, induced emf would be awesome!
SecretAsianMan7 1 year ago 27
Love these circuit problems!
WTFnigga001 1 year ago 2
In what way is this hairy? It's all linear, in that you can simply solve for one thing at a time.
nutnub1 1 year ago
I don't get this, you say that the voltage is the same at any point in the circuit, but in this problem i have the V is 100v, and she says that V3 is 6v. I thought it was the same no matter where you are on the circuit
max1916251080 1 year ago
@max1916251080 In the parallel portion of the circuit the voltage is constant across each "branch". But if there are portions in series then there are voltage drops across these series-resistors sections. So there are voltage drops across these collection of "branches"
jakeo3553 1 year ago
Thanks for all the video's so far, they have helped me a lot with my studies!
But im still left with some questions about circuits; what will happen if you add mutiple U's (dunno the word :-) ) intro the circuit? What will happen with the flow of electrons? And what will happen if you put them in parallel?
Thanks for your clear video's! Looking forward to the new video's!
franknostradamus 1 year ago
WOW this video explained it so well, haha the other day i was struggling with the text book to understand this =D your greatt thankss :)
lightningblade79 1 year ago
my god, this is more confusing that getting into orbit in orbiter O_o still, I get it, thank you for your time and effort khanacademy :)
KKinsane2009 2 years ago 2
excellent .the way of explanation s awesome.thank you very much.expecting more
itsnamed 2 years ago 2
YES! I got the right answer before you even finished explaining! Thank you!!!!
hugtheoboe 2 years ago
GJ GJ MAN GJ hahah great tutorial buddy
xxfuturerevealedxx 2 years ago
How can the amperage be 8 amps if every branch of the parallel circuit is different?
Ritzoid 2 years ago
kirchhoff's current law
Nervasin 2 years ago
it's 8A in total but this is shared amongst the parallel resistors(pathways), that's the whole point of the video!
ajskilton 2 years ago
Watch it again and again until you get it or go back one video you'll then know it forever.
bellatesla 2 years ago
I need a RC circuit video... lol Thank you for the videos on circuits in series and parallel!
VWinUgo 2 years ago 18
lo RC is really more complicated...
jbohbot1 1 year ago
Comment removed
foamysol3 2 years ago
i got 2.5!!!!!!
woodenjaw 2 years ago
lol i got like, way off!
jbohbot1 2 years ago
thanks for your kindness and generosity to put up this vid for those physics learners/. :)
youriemhei 2 years ago
thanks for the vid bud
zackalphaomega 2 years ago
I disagree with the comment below to some extent, only because some stuff you draw I can't read but you say what it is out loud as you are drawing it so I know what it is.
These videos by the way are awesome, thanks for putting them up!
jmnc05 2 years ago 2
This has been flagged as spam show
i'd suggest . . . no, i would plead that you re-rercord these chapters AFTER you have written a script and rehearsed. if you listen to the presentation with your eyes closed, and/or watch without volume, i think you might agree. some one with no basic concept could easily get lost and give up in frustration. the information is all there however the dialogue wanders occaisionaly and the sketches and equations can be difficult to to take notes, for later review. thanks sc
sc9stl 2 years ago
how do you calculate current through each ones and the voltage through each one
hacksign000 2 years ago 2
the voltage at each resistor is just the voltage drop. to find this you first have to know the current going through all the resistors in the series configuration shown at the end, this is 8 amps, then you multiply the total current by each resistance. The current through each resistor in series is the same for the equivalent circuit, and in parallel resistors the voltage across each resistor is the same so you can use ohm's law to find current.
Nervasin 2 years ago
totally understood. thank you .
polos505 2 years ago
Comment removed
brentwoodbc 2 years ago
There isn't a math error. (1/Rt)=(1/4)+(1/8)+(1/16)+(1/16). The way its written the last (1/16) looks like (1/4) but its really (1/ the resister on the bottom of the group hes evaluating.
fussners 3 years ago
2:51
magicwisard10 3 years ago
Thanks man, You're Awesome :)
bboy1600 3 years ago
This comment has received too many negative votes show
Pretty sure there is a math error at 2:45. It should be (4+2+1+4)/16.
You get the point across anyway.
L1nnaea 3 years ago
Look at fussners comment up there.
plo1T 2 years ago
Great video!
gerardosilva1980 3 years ago
I wish the lectures on magnetism weren't under construction :(
If light and optics are added, attending physics class will not be necessary!
Thank you very much for everything you've done Sal! Your much appreciated.
-PsubD
anava84 3 years ago
Thank you !
idricool 3 years ago
Thanks for saving my grade again!! Great videos, I'm loving them :)
tiptopmini 3 years ago
actually I don't get voltage dividers and EMf......(sneakily asking you to do a video on it!!)
Nandine2 3 years ago 3
wow great video, although I don't really have problems understanding electronics in my physics class but this video really does give an intuitive feel. and I am not just saying that!
Nandine2 3 years ago