Mathematical Induction (Part II)

[j123456young]

the voice is slower than a tortoise, bt the explanation is faster than a ferrari in german motorways. wz completely lost

[kingofdice66]

yes...it is balid :)



[Haseebbaloch786]

IT IS A GREAT VIDEO

HELPFULL FOR THE STUDENTS WHO WERE STRUGGLING TO LEARN MATHEMATICAL CONCEPTS.

THANKS FOR YOUR VIDEO

[kingofdice66]

you are not a good math teacher, you do not teach math here on youtube, i....don't know what the hell you are doing, but certainly not teaching math, honestly .........you suck, maybe you would be good on ......math history maybe

[Logic4Dummies]

induction is P(1) & [P(k)-->P(k+1)]

[sunrise3500]

I don't follow the math. Could you explain why at the n+1 step. it was 3^n *3 > 3*3k+3 instead of 3^n * 3 > 3* 3k + 1? Did it not come from 3n+1 ? so 3(n+1) + 1 did not become 3n + 3 + 1?

Thanks,

Sury

[ynceraj]

You start from 3^k> 3*k+1 and then you multiply both sides of the inequality by 3 so you get 3^k*3>(3*k+1)*3 notice the parentheses. So multiplying the right side

3^(k+1)>3*3*k+1*3 and that is

3^(k+1)>9*k+3. Is that better?

[sunrise3500]

hmm it didn't occur to me before to multiply both side. I just thought you do (k+1) multiply by the coefficient but everything outside go unaffected. I suppose it make sense to multiply the whole right side by 3 since 3^k+1 really is 3^k * 3. Thanks for the clarification.

[ynceraj]

You multiply by 3 because is the easiest way to get 3^(k+1) from 3^k

[fargus93]

its a fucking robot talking. haha but seriously you are going a little fast.

[ynceraj]

been called many things in my life you are the first one to call me a robot :-)

Thanks it must be a compliment!

Thanks for your suggestions

[korrisha]

dont go to fast next time tooo tooo fast I need to know what is the name of the program you used though

[ynceraj]

I will try to go slower next time

really sloooow :-) just kidding

I use Corel Painter and for screen recording

Camtasia. Regards

[as89han]

Great video...helped a lot..

Was wondering do you need to prove it all the way upto 6k>1 or can u stop at 3^(k+1) > 3 (k+1)+1

[ynceraj]

Is not at all obvius that 3^(k+1) > 3 (k+1)+1 is true. Therefore a proof is needed.

Usually people will stop at 6k>1 but some people may also required a prove of that.

And that can also be done again by induction! :-)

[as89han]

excellent lesson..hope u put up more on different topics..Thanks

[donotloiter]

This is a great explanation. You should make more videos about induction and proofs.

[ynceraj]

I have more videos about math at my site. see address on top right.

[twentysevenne]

really helpful thanks

but you sound really bored lol

[jasondh22]

Excellent video!