The real way to prove 2=1. Write it on paper to understand better.
Take 2 as 2/1. Then multiply this by infinity/infinity (anything divided by itself is 1, so the 2/1 will stay as it is since you are multiplying by 1). Infininity x anything is just infinity. Therefore 2 x infinity is infinity and 1 x infinity is infinity. Therefore 2/1 x infinity/infinity = infinity/infinity = 1.
The problem is on step 3. In step 3, both sides subtract 2XY. In the left hand side, 2X^2 - 2XY actually is equal to zero. In the right hand side X^2 - XY is equal to zero too. Since both sides are equal to zero, the factoring in step 4 become meaningless as any number times zero will result zero. Thus this video is a gabbage.
you are all idiots: X^2-XY is one of the last steps and if you can remember that X=Y so what you are saying is that (Y^2 -YY) which does = 0 so, you just proved that 0=0 well done.
Try this on for size: Assume x does not = 0... though it is implied in this next step. Let x = 1+1+1+...+1 (x times) [Multiply both sides by x] x^2 = x+x+x+..+x (x times) [Take the derivative of both sides with respect to x] 2x = 1+1+1+...+1 (x times) [By our original definition of x, substitute] 2x = x [Divide by our non-zero x] 2 = 1 What's the mistake?
Equivocation -- you defined x to be a constant, then differentiated the functions f(x)=x^2 and g(x)=x+x+... (x times). Using the same line of reasoning and treating x as a constant throughout leads to 0=0.
it has nothing to do with division by zero... it has to do with the fact that both sides of his equation were multiplied by zero. x*0 = y*0 for any values. he could've made his claim without actually "dividing by zero"; if 2x = 1x (for any x that isn't 0), 2 = 1. the catch is that in this case... x = 0. funny stuff, youtube mathfolk. i really enjoy ignorant folk using big words like "invalid", "thus", and "fallacy".
Yu ARE allowed to assume y=x just as if u said ricky can lift the same amount of weight as john. the problem is that if y=x than y-x=0 and you can't divide by zero. Anything divided by 0 is undefined.
the only problem was the factoring they would factor like this 2x(x-y)=x(x-y) divide by x-y and you get 2x=x which is only true with 0 but any other number will work like 1=2 or 2=4 or pretty much any number multiplied by 2 everything else is mathematically sound.
HAHAHA...... u took benefit of concept 2*0=1*0. but here we can"t do 2=1*0/0 as 0 divided by o will become indeterminate. BUT u have hidden the 0 here in algebric form of X^2 - XY. now u cancel X^2 - XY/X^2 - XY =1 which is wronge BECAUSE X^2 - XY = 0 as u assumed before X=Y. it wud have worked in any other case when X not equal to Y.
I got it! In step 4, all = 0. And then it's wrong in step five to take that away! So it goes from 0=0 (which is right) to 1=2 (which is wrong). Good trick!
You can presume x=y... But once you random assign values to it... which you did by applying it to the equation 2=1.... Is wrong, you cannot enter unknown/unset algebriac values into a set equation...
Your mistake was that x*x=x*y so actually x*x-x*y=0 You divided both sides with zero and that is the mistake because you cant devide both sides with 0.If we could do that it would ment that 1=2=3=4=5......=123123=..... How?this is how:
x , y are some numbers( they can be any numbers)
If we say that x=y we can devide both sides with any number and the equivalation will stay the same .If we devide both sides with zero we get this 0=0 and that is true.With the law of implication x=y, 1=2=3..
2(X^2 - XY) = (X^2 - XY) is possible only if the (X^2 - XY) is equal to 0. So we've got that (X^2 - XY)=0 you cannot devide with 0. There is the fail.
they are not kidding you man, but what you did is that you used the definition in the wrong way!
the definition says : a.b =c.b then a=c iff b!=0 ( b not equals to 0) and you assumed that x=y and you divided by x*x - x*y => 0 and you can't divide by 0
The mistake is the division by x^2-xy. Since x=y, this is the same as dividing by xy-xy, which is 0. And that always seems to be the fallacy in these types of math teasers. Cool video.
Okay, I really like this question, so first off, I would like to thank you for posting this video up. Now the flaw: in step five, when you divided both sides by (x^2-xy), essentially, you are dividing by 0 because if we sub in "x" for "y" (stated at the beginning), we get the following:
(x^2-x*x) = (x^2-x^2) =0
Therefore when you conduct step five, you are, in essence, dividing by zero, which is unallowable. Nice video though, I'm looking forward to more. Thanks.
Okay, I really like this question, so first off, I would like to thank you for posting this video up. Now the flaw: in step five, when you divided both sides by (x^2-xy), essentially, you are dividing by 0 because if we sub in "x" for "y" (stated at the beginning), we get the following:
(x^2-x*x) = (x^2-x^2) =0
Therefore when you conduct step five, you are, in essence, dividing by zero, which is unallowable. Nice video though, I'm looking forward to more. Thanks.
your problem is actually that x squared and xy are the same since x and y are equal. so the equation x squared - xy equals 0; at the end of the equation you divide by x squared - xy, which is of course 0; which is of course mathematically illegal. you will be fined. maybe you should think of that before you break the law, son!
Dude, when it is "assumed" that x=y, we aren't saying the letter x "is" the letter y. x and y are representations so saying x=y isn't a logical fallacy or absurd.
It's like saying I have two different symbols that represent the same quantity. And that being the case, it's mathematically correct to say those two symbols equal one another.
although your videos are pretty good brainteasers, i have to say, will you ever do something that isn't essentially pre-algebra? i mean, sure, these are pretty fun, i guess, but after a while they get kinda boring... -.- just saying... if you could get some geometry or even some pre-calculus tossed in, then i would appreciate you videos a little more. but still, for someone who might not be so great at math, your videos are pretty good rack-your-brainers. =)
You said that x=y. So when you say divide by "(x^2-xy)" you're essentially saying x^2-x^2 or y^2-y^2, these both equal 0 (same number - same number = 0). You can't divide by 0, it just doesn't exist. There in lies the problem <3
i think its cause you divided by (x^2-xy), you can't do that because if x=0 then you just divided by 0 in which case this won't work, to fix this you need to assume x isn't 0.
the last step is WRONG!!!! x^2-xy=0 . no matter what values x has . lets say x=5, then y=5 so 5^2-(5)(5)=0 , so dividing by x^2-xy is not correct. in mathematics any number divided by 0 is undefined. (good try though : D)
@PNDeads To be fair, division by zero is not always undefined: it depends on what you are up to. Often in calculus, depending on the limit, it equals positive or negative infinity. :)
We can state that anything to the power of zero will always equal 1, any given number^0 = 1, so working backwards, we can logicaly state that ^0rad1 = any given number. Now after much thinking and unnecessary government funding, top mathematicians can firmly state that numbers 1 and 2 are in fact "any given numbers". Therefore, we can definitively state that 1=2
ur problem happened right at the start, u cant assume x=y - because if u drew this line ona graph then they would both be exact the same number and not 1 and 2 - therefore it is just a silly mistake - did u make this mistake on purpose just to make this video?
ur problem happened right at the start, u cant assume x=y - because if u drew this line ona graph then they would both be exact the same number and not 1 and 2 - therefore it is just a silly mistake - did u make this mistake on purpose just to make this video?
Like many people don't understand, I am allowed to assume x=y. That's a perfectly legal mathematical situation to assume at the beginning of the problem. As long as I always assume x=y then I'm fine.
@mayarrow Did you write this comment to purposefully portray yourself as a moron? The mistake is dividing both sides by x^2-xy. This is impossible as x^2-xy = 0.
My Physics teacher is also a big lost fan... what's with numbers, that makes people like lost?? or what's with lost, that attracts numbers likers ??? hmm...
@mrjames113083 okay for the 1000 time a day i see videos like this.. OKAY SO you divide by (x2 - xy) x2 = x.y so that means you divide by ZERO .. seriously... every video of 2=1 0=1 or so is the same..everyone divides by zero .. you are BULLSHIT , im sorry , im really , really sorry
@mrjames113083 Eh, that don't mean nothing. I have one of those BS in mathematics things, and I come up with garbage that's sloppy and full of errors too.
It comes when you factor out the equation. You take the two and move it to the outside, as if you were going to multiply times two the equation inside of the brackets. However, you didn't devide the 2 in with the equation, you're changing it, and making it appear at the end you're left with 2=1, when in reality, you have to devide the WHOLE solution by (x2-xy), thus, in reality, the real solution is
0=0.
I think. Dare I say there are to many... VARIABLES. Ohhh, that's funny...
This is the actual error committed in the video, For sure. Because X = Y is the primary assumption. So 2 (X² - X.Y) = (X² - X.Y) goes 2*0=1*0. So this is mathematically wrong because we cant divide anything by 0. Hope this answers the mistake.
This is the actual error committed in the video, For sure. Because X = Y is the primary assumption. So X² = X.Y goes 0=0. So this is mathematically wrong because we cant divide anything by 0. Hope this answers the mistake.
There is no mistake. Only in the final conclusion. Because X^2- X.Y will be always zero because X=Y. And 2 times 0 it´s equal to 1 times 0. This problem don´t have the solution of 2=1 but of 2/1=0/0 which is an indetermination, in this case any X you chose wil be a solution.
we know, since x=y, that x squared - y equals zero...no dividing by zero! It's not allowed. Thus, the error.
p.s. I love your LOST videos...way better than Seanie B, because you upload them faster and just give us the good stuff, not a long boring recap of every detail!
lets say both x and y (because they are equal) are 5
25-5 doesnt equal 0 it equals 20
i dont know the problem with the equation in the video, but i know there is definitely a major flaw in your crappy logic
now i am not usually this rude, but you pissed me off about your comment on seanie b's videos. he makes such in depth recaps because some of his vieweres dont want to hear irrelevant topics lik james puts in his vid
doctorB92, Thank you for catching my error. I am embarassed that I made such a simple mistake. Here, I have since fixed the mistake:
we know, since x=y, that x squared - xy is essentially x squared - x squared, which equals zero...no dividing by zero! It's not allowed. Thus, the error.
p.s. I love your LOST videos (No offense is meant toward Seanie B or any of his followers.)
lets say both x and y (because they are equal) are 5
25-5 doesnt equal 0 it equals 20
i dont know the problem with the equation in the video, but i know there is definitely a major flaw in your crappy logic
now i am not usually this rude, but you pissed me off about your comment on seanie b's videos. he makes such in depth recaps because some of his vieweres dont want to hear irrelevant topics lik james puts in his vid
this is all based on the assumption that x=y. He begins with x=y and adds and multiplies variables to both sides of that equation and eventually comes up with 2=1. Unfortunately, x does not = y and that is the error.
the 0/0 indeterminacy. Actually you guys are all dumb. It's the assumption that 0/0 is equal to any one number that's wrong. 0/0 is effectively equal to all numbers(including 2). The problem is that you assumed that it is only equal to 1. Since x=y, then x2-xy/x2-xy is 0/0. However, this does not mean that x2-xy/x2-xy is equal to 1. The typical explanation is that you can't divide by zero. You can; you just can't assume that this 0/0 is equal to one.
Ironically, all the explanations on this page are wrong. 1. You can divide by squares accurately. 2. This is not a proof of 0=0. It is a proof of 0/0 = any number. 3. x and y don't have to be equal to zero. x2 - xy has to be equal to zero. Which is shown in the beginning by the assumption x=y. 4. You can, in fact, divide by zero. The problem is when you assume that x/0 is equal to some specific number. When x does not equal 0, x/0 is equal to + or -infinity. When x=0, x/0 equals any number.
Actually, it is possible to divide by zero. In many contexts, it is important to recognize this fact. 0/0 is the classical mathematical exploration called the indeterminacy, which I explained below. In other cases, like some aspects of quantum physics, it is important to recognize that any number divided by zero is infinity. I understand why you may shrug off the concept and simply decide that you cannot divide by zero. But that is an unfounded and incorrect generalization.
I guess that is a fair enough claim. However, it is necessary in many fields beyond simple arithmetic, making it an important philosophical point that it can be done. Although you are correct that it is usually done in the context of some limit, when used in many physics-based applications, it is used outside the context of limits as well. For most mathematical purposes we assume that it is undefined, however doing so is mainly just hair splitting as a result of it's unnecessary results.
For instance, in a field if we assume division by zero to have a result, it must not only be + infinity but also - infinity. This is extraneous in most broad math contexts. However, when dealing with gravitational singularities, it becomes necessary to consider x/0 an appropriate maneuver.
The proof I've provided in my last comment cannot be denied. As you started with assumption that X=Y so in the whole process we can use both of them at each others place. And when u do that in step 4 both sides go to zero. It actually proves mathematical fact that 0=0 not 2=1
Step 4: 2(X2-XY)=(X2-XY) (Read X2 as X square) As X=Y according to our fist assumtion,
So 2(X2-X2)=(X2-X2)
or 2*0=0
or 0=0
Thats what it's all about. In step 4 its just like both sides r multiplied by zero and he divides both sides by zero to eliminate it which is not possible.
Comment removed
IGNsucks 3 months ago
The real way to prove 2=1. Write it on paper to understand better.
Take 2 as 2/1. Then multiply this by infinity/infinity (anything divided by itself is 1, so the 2/1 will stay as it is since you are multiplying by 1). Infininity x anything is just infinity. Therefore 2 x infinity is infinity and 1 x infinity is infinity. Therefore 2/1 x infinity/infinity = infinity/infinity = 1.
BOOM
kieranm310 4 months ago
If X=Y, then XY is the same as X^2, so X^2 - XY = 0, so you divided 0 by 0 at the end.
kieranm310 4 months ago
dividing by zero
justiLiang 4 months ago
i wanted to be that guy until you said youd be mean to me and we have to be in a classroom together til june so ill be quiet now :D
thepurplevoid 5 months ago
im assuming he was challenging you guys to find the error i think he already knew it was wrong
tayoyoyo 7 months ago
Nearly all false proofs result from the fact that you are dividing by 0 at a point.
Hello59239 8 months ago
The problem is on step 3. In step 3, both sides subtract 2XY. In the left hand side, 2X^2 - 2XY actually is equal to zero. In the right hand side X^2 - XY is equal to zero too. Since both sides are equal to zero, the factoring in step 4 become meaningless as any number times zero will result zero. Thus this video is a gabbage.
stevechung99 8 months ago
you are all idiots: X^2-XY is one of the last steps and if you can remember that X=Y so what you are saying is that (Y^2 -YY) which does = 0 so, you just proved that 0=0 well done.
TheMarky606 9 months ago
DDOGGSWINCHY 9 months ago
@DDOGGSWINCHY
Equivocation -- you defined x to be a constant, then differentiated the functions f(x)=x^2 and g(x)=x+x+... (x times). Using the same line of reasoning and treating x as a constant throughout leads to 0=0.
ModeratelyGreen 8 months ago
it has nothing to do with division by zero... it has to do with the fact that both sides of his equation were multiplied by zero. x*0 = y*0 for any values. he could've made his claim without actually "dividing by zero"; if 2x = 1x (for any x that isn't 0), 2 = 1. the catch is that in this case... x = 0. funny stuff, youtube mathfolk. i really enjoy ignorant folk using big words like "invalid", "thus", and "fallacy".
troll (correct troll, i might add) out.
boddah2772 10 months ago
Yu ARE allowed to assume y=x just as if u said ricky can lift the same amount of weight as john. the problem is that if y=x than y-x=0 and you can't divide by zero. Anything divided by 0 is undefined.
smk2312 10 months ago
x^2-xy=0, you can't divide by zero ya dunce XD
eajags2825 10 months ago
A you divided by zero. B you should know that dividing out a variable creates a loss of values
v9guitarhero1425 10 months ago
Division by zero is an invalid operation, and thus the proof is a mathematical fallacy.
DevoutSkeptic 1 year ago
you cant divide by 0 x^2 - xy is equal to 0
adoolie 1 year ago
So you just proved that 2(0) = 1(0). We knew that.
JasonHouston77 1 year ago
x^2=xy, so x^2-xy = xy-xy which is 0.
softwarez4free 1 year ago
WOW THIS IS AWESOME!!!! I'VE NEVER SEEN ANYONE DIVIDE BY ZERO SO AWESOMELY BEFORE I WATCHED THIS VID!!!!! WOO-HOO DIVIDING BY ZERO!!! YEAH!!!!!!
Sheldonsheldon109 1 year ago
This has been flagged as spam show
Here is the issue: you divide by (X^2 - XY), but since X^2=XY, you are dividing by zero, which is not possible.
Samcollins3 1 year ago
Here is the issue: you divide by (X^2 - XY), but since X^2=XY, you are dividing by zero, which is not possible.
Samcollins3 1 year ago
the only problem was the factoring they would factor like this 2x(x-y)=x(x-y) divide by x-y and you get 2x=x which is only true with 0 but any other number will work like 1=2 or 2=4 or pretty much any number multiplied by 2 everything else is mathematically sound.
phister7 1 year ago
you cannot divide x squared minus xy from each side. it's so simple.
jmfooter14 1 year ago
@jmfooter14 that's the thing about math it IS simple.
bluewisdomtriforce 1 year ago
Oh my god! my brain just melted.
Daddypickles 1 year ago
It is because you are dividing by zero. Any integer for x will result in a divide by zero error.
TechnoSquirrel 1 year ago
HOLY FUCK I'M THE 6,666th VIEWER.
xxMrSaGgYxx 1 year ago
@xxMrSaGgYxx are you the antichrist?
slovakmath 1 year ago
You divide the last step by 0!
As all mathematicprofessors and all scentists know,
ONLY CHUCK NORRIS CAN DIVIDE BY 0!
albinoslam1970 1 year ago 5
2 (mod 1)=1
MasterGfox 1 year ago
HAHAHA...... u took benefit of concept 2*0=1*0. but here we can"t do 2=1*0/0 as 0 divided by o will become indeterminate. BUT u have hidden the 0 here in algebric form of X^2 - XY. now u cancel X^2 - XY/X^2 - XY =1 which is wronge BECAUSE X^2 - XY = 0 as u assumed before X=Y. it wud have worked in any other case when X not equal to Y.
liked the video.
broulys1729 1 year ago
in the last step, you are dividing by zero
since x=y, and by allowing the division of the factor (x^2-xy), you are committing a fallacy.
chaceburke 1 year ago
you divided by zero its undefined
thelastthingwedo 1 year ago
Beautifully done! And a very entertaining way of dividing by zero.
spacebender 1 year ago
since x=y ,x-y=0,x^2-xy=0,we cannot divide by zero on boyh sides
9867168304 1 year ago
(X^2-XY)=0. In the ladt step, you divided by (X^2-XY), that means you divided by 0, whith you can't do. That what's wrong.
Berntisso 1 year ago
my head hurts... i suck at maths XD
darkjackal17 1 year ago
I got it! In step 4, all = 0. And then it's wrong in step five to take that away! So it goes from 0=0 (which is right) to 1=2 (which is wrong). Good trick!
ThePlanetCube 1 year ago
i hate when titles have lies in them xD
MirageScience 1 year ago
You can presume x=y... But once you random assign values to it... which you did by applying it to the equation 2=1.... Is wrong, you cannot enter unknown/unset algebriac values into a set equation...
Marushuki 1 year ago
If X = Y, then X^2 - XY is the same as X^2 - X^2, which is zero. Then you divide by that, which is division by zero, which is ILLEGAL.
jkatz94 1 year ago
Your mistake was that x*x=x*y so actually x*x-x*y=0 You divided both sides with zero and that is the mistake because you cant devide both sides with 0.If we could do that it would ment that 1=2=3=4=5......=123123=..... How?this is how:
x , y are some numbers( they can be any numbers)
If we say that x=y we can devide both sides with any number and the equivalation will stay the same .If we devide both sides with zero we get this 0=0 and that is true.With the law of implication x=y, 1=2=3..
Naruto19875 1 year ago
failure is where u divide by (x^2 -xy). as x = y, that equals 0. dividing by zero!!!! fail. good trick tho
warriorrabbi 1 year ago
2(X^2 - XY) = (X^2 - XY) is possible only if the (X^2 - XY) is equal to 0. So we've got that (X^2 - XY)=0 you cannot devide with 0. There is the fail.
riflleman 1 year ago
they are not kidding you man, but what you did is that you used the definition in the wrong way!
the definition says : a.b =c.b then a=c iff b!=0 ( b not equals to 0) and you assumed that x=y and you divided by x*x - x*y => 0 and you can't divide by 0
Monah84 1 year ago
if x=y then x^2-xy =0 and you cannot divide by zero you should have infinity=infinity as x^2-xy tends to zero
molybdenite1 1 year ago
The mistake is the division by x^2-xy. Since x=y, this is the same as dividing by xy-xy, which is 0. And that always seems to be the fallacy in these types of math teasers. Cool video.
Iambenthejew 1 year ago
Okay, I really like this question, so first off, I would like to thank you for posting this video up. Now the flaw: in step five, when you divided both sides by (x^2-xy), essentially, you are dividing by 0 because if we sub in "x" for "y" (stated at the beginning), we get the following:
(x^2-x*x) = (x^2-x^2) =0
Therefore when you conduct step five, you are, in essence, dividing by zero, which is unallowable. Nice video though, I'm looking forward to more. Thanks.
hmg9 1 year ago
Okay, I really like this question, so first off, I would like to thank you for posting this video up. Now the flaw: in step five, when you divided both sides by (x^2-xy), essentially, you are dividing by 0 because if we sub in "x" for "y" (stated at the beginning), we get the following:
(x^2-x*x) = (x^2-x^2) =0
Therefore when you conduct step five, you are, in essence, dividing by zero, which is unallowable. Nice video though, I'm looking forward to more. Thanks.
hmg9 1 year ago
It's easy..in the final part you divided by 0..because there is 2(X²-XY)=(X²-XY), in which clearly you cant divide by X²-XY..
caneboia 1 year ago
geez...
Creolebway 1 year ago
well heres how you can see the flaw, replace x and y with a number like 2, because its easy to work with (im doing the lines by the steps)
2=2
4=4
8=8
0=0
factoring : 2(4-4)=(4-4) {still true}
heres the flaw: when you subtract x^2-xy you get 0, and you cant divide by 0
aibballstar23 1 year ago
your problem is actually that x squared and xy are the same since x and y are equal. so the equation x squared - xy equals 0; at the end of the equation you divide by x squared - xy, which is of course 0; which is of course mathematically illegal. you will be fined. maybe you should think of that before you break the law, son!
koolk9steph 1 year ago
Isn't x^2 + x^2 really x^4, not 2x^2?
redniwediS 1 year ago
you can't divide by x^2-xy it's equal zero since x=y so x^2-x^2=0
ama11ma 1 year ago
X-y = 0, dividing by zero is irrational. therefore your logic is false.
SuperSonicSpeed1000 1 year ago
Nice trick, reminds me of proving 0.999....=1. Do you know that one?
Yeah, (x^2 - xy) = (x^2 - x^2) = 0 (x = y). So, of course, dividing by zero produces crazy things.
highaerials36 2 years ago
you are assuming that x^2-xy DOESN'T EQUAL ZERO on the last step. because any # divided by zero is undefined.
1rubenherrera1 2 years ago
If x=y then x^2-xy=0. You cannot divide by 0, therefore the argument is flawed.
MrSixpack23 2 years ago
Comment removed
MrStarstruck5 1 year ago
This comment has received too many negative votes show
Why the fuck should we simply assume that x = y? They are two different letters.
VitalSigns1 2 years ago
LOL...i hope your jk
nickwkcin 2 years ago
No seriously tell me why I should assume something that is absurd?
VitalSigns1 2 years ago
Dude, when it is "assumed" that x=y, we aren't saying the letter x "is" the letter y. x and y are representations so saying x=y isn't a logical fallacy or absurd.
It's like saying I have two different symbols that represent the same quantity. And that being the case, it's mathematically correct to say those two symbols equal one another.
nickwkcin 2 years ago
ok now I get it
VitalSigns1 2 years ago
@vitalsigns1
in the simplest way to say this possible, you're stupid
guineapigsRus1996 1 year ago
although your videos are pretty good brainteasers, i have to say, will you ever do something that isn't essentially pre-algebra? i mean, sure, these are pretty fun, i guess, but after a while they get kinda boring... -.- just saying... if you could get some geometry or even some pre-calculus tossed in, then i would appreciate you videos a little more. but still, for someone who might not be so great at math, your videos are pretty good rack-your-brainers. =)
origamiguy91 2 years ago
Reminds me the fact that
n∞ = ∞
heloizyjhenifer 2 years ago
You said that x=y. So when you say divide by "(x^2-xy)" you're essentially saying x^2-x^2 or y^2-y^2, these both equal 0 (same number - same number = 0). You can't divide by 0, it just doesn't exist. There in lies the problem <3
bungeemonkey823 2 years ago
u cant to 0/0 doesnt work
x-1
over
x-1
this isnt 1 cos it is 0/0
mayarrow 2 years ago
btw dudes, he knows theres a mistake, he wants u to find it!
ohadisgreat 2 years ago
i think its cause you divided by (x^2-xy), you can't do that because if x=0 then you just divided by 0 in which case this won't work, to fix this you need to assume x isn't 0.
ohadisgreat 2 years ago
guess your gonna have to ask jacob
GEALT09 2 years ago
lololololol
lasvegasty 2 years ago
Since X = Y, (X2 -XY) = 0, and you CANNOT DIVIDE BY ZERO :)
BerendBotje123 2 years ago
also...................
there are people that dont know maths...
you have not to post videos like that because people then will say things like...
"Oo maths are wrong....."
Manysdugjohn 2 years ago
AHHH NO MORE MATH MY BRAIN HURTS!!!
shadowgun29 2 years ago
the last step is WRONG!!!! x^2-xy=0 . no matter what values x has . lets say x=5, then y=5 so 5^2-(5)(5)=0 , so dividing by x^2-xy is not correct. in mathematics any number divided by 0 is undefined. (good try though : D)
PNDeads 2 years ago 15
@PNDeads To be fair, division by zero is not always undefined: it depends on what you are up to. Often in calculus, depending on the limit, it equals positive or negative infinity. :)
Chokoretokukki 1 year ago
@PNDeads So it is a proof for "any number divided by 0 is undefined", not for "2=1".
justsmilehomie 9 months ago
x=y
so x=1; y=1
x-squared= 1
xy=1
1-1=0
and you cannot divide by 0!
Darkmagician1422 2 years ago
Yeah funny!!
I think that everything is correct. except the LAST Step that is wrong!
Because you don't have the right to divide by
(x^2 -xy) because in case where x = 0 it give 0/0 which is undefined
But not sure . . .
reinfermiert 2 years ago
Assuming that x = y is the fault, as x being equal to 2 and y being equal to 1.
Dalekman911 2 years ago
We can state that anything to the power of zero will always equal 1, any given number^0 = 1, so working backwards, we can logicaly state that ^0rad1 = any given number. Now after much thinking and unnecessary government funding, top mathematicians can firmly state that numbers 1 and 2 are in fact "any given numbers". Therefore, we can definitively state that 1=2
adaybefore 2 years ago
Because x cannot equal 0 this proof can be proven false
futureredsock 2 years ago
meow !!
chupachups1905 2 years ago
делить на 0?? оч смешно
tden000 2 years ago
WAIT a second...
Since we know Xsquared is equal to XY, why in step 3 can the left side of the equation not be changed to 0? 2Xsquared subtract 2XY would be zero...
The right hand side would also be zero XY subtract XY is zero (leaving Xsquared) and Xsquared subtract XY is also zero...
ARGH! Actually this sort of proves my other comment about X not equalling Y incorrect.
freudianslap 2 years ago
Surely at the beginning... X never equals Y? Maybe?
freudianslap 2 years ago
x = 1/2 ?
HaagenDaz13 2 years ago
This has been flagged as spam show
ur problem happened right at the start, u cant assume x=y - because if u drew this line ona graph then they would both be exact the same number and not 1 and 2 - therefore it is just a silly mistake - did u make this mistake on purpose just to make this video?
mayarrow 2 years ago
ur problem happened right at the start, u cant assume x=y - because if u drew this line ona graph then they would both be exact the same number and not 1 and 2 - therefore it is just a silly mistake - did u make this mistake on purpose just to make this video?
mayarrow 2 years ago
Like many people don't understand, I am allowed to assume x=y. That's a perfectly legal mathematical situation to assume at the beginning of the problem. As long as I always assume x=y then I'm fine.
mrjames113083 2 years ago 13
@mrjames113083 i'd love you as maths teacher, mine had no personality what so ever.
zosko1 1 year ago
@mrjames113083
Yes you can assume whatever you want in the begining. True enough.
But you must follow the assumption as TRUE until the end right?
So X = Y means X*X = X*Y, so BECAUSE OF YOUR ASSUMPTION (X*X) - (X*Y)=0
and you can NOT divide by zero. Am i right?
So the division by zero (witch of course is a mistake) creates the paradox.
ShadowDreadblade 1 year ago
@mayarrow Why not?
Berntisso 1 year ago
@mayarrow Did you write this comment to purposefully portray yourself as a moron? The mistake is dividing both sides by x^2-xy. This is impossible as x^2-xy = 0.
ivasenko48 9 months ago
Hey Mr James : )
I'd just like to ask out of curiousity, if you have any further math qualifications since leaving high school. If so, what are they?
I ask this because you seem to have a telent for math.
Please leave a comment above mine as I'd like to know. Thank you.
cozzaboi2k8 2 years ago
I have my BS in Mathematics. I have one year professional teaching experience and continue in my career as a math teacher.
mrjames113083 2 years ago
My Physics teacher is also a big lost fan... what's with numbers, that makes people like lost?? or what's with lost, that attracts numbers likers ??? hmm...
silda22 2 years ago
@mrjames113083 okay for the 1000 time a day i see videos like this.. OKAY SO you divide by (x2 - xy) x2 = x.y so that means you divide by ZERO .. seriously... every video of 2=1 0=1 or so is the same..everyone divides by zero .. you are BULLSHIT , im sorry , im really , really sorry
dekomondo 1 year ago
@mrjames113083 Eh, that don't mean nothing. I have one of those BS in mathematics things, and I come up with garbage that's sloppy and full of errors too.
theboombody 1 year ago
That's why you shouldn't divide by zero.
VHASE 2 years ago 2
It comes when you factor out the equation. You take the two and move it to the outside, as if you were going to multiply times two the equation inside of the brackets. However, you didn't devide the 2 in with the equation, you're changing it, and making it appear at the end you're left with 2=1, when in reality, you have to devide the WHOLE solution by (x2-xy), thus, in reality, the real solution is
0=0.
I think. Dare I say there are to many... VARIABLES. Ohhh, that's funny...
Gamingtrevor 2 years ago
lol
barrieboy58 2 years ago
Comment removed
FireofPrometheus 2 years ago
if x=y than x² = x*y
so x² - x*y= 0
but its not allowed to dived with 0 :)
Marotzke 2 years ago 2
any number divide by 0 will get infinity...
but 0 divide by 0 willl get 3 answers:
1 or 0 or infinity..
because:
a) any number/0 = infinity
b) 0/any number = 0
c) when two same numbers are divide each other, the result is 1.
anyone..correct me if I'm wrong.thanks.. (^^,)V
drc4rd1n 2 years ago
I dont know y u have put my explanation as spam???? You asked the mistake and I proved that...
JerryVikram 2 years ago
I didn't mark it as spam. Anyone can spam a comment. If I didn't like a comment, I have the authority to remove it. Obviously I didn't.
mrjames113083 2 years ago
yes..we can spam a comment actually..
drc4rd1n 2 years ago
x=y? not possible!!!!!
if they are diferent letters they represent diferent numbers
i am 14 years old and i know that
StatusMaciza 2 years ago
and you are retarded
lynxkills8 2 years ago
just keep silent pls
drc4rd1n 2 years ago
This has been flagged as spam show
I got the simpler version ...
0 = 0
2 * 0 = 1 * 0
Divide both the sides by 0 to get
2=1.
This is the actual error committed in the video, For sure. Because X = Y is the primary assumption. So 2 (X² - X.Y) = (X² - X.Y) goes 2*0=1*0. So this is mathematically wrong because we cant divide anything by 0. Hope this answers the mistake.
JerryVikram 2 years ago
I got the simpler version ...
0 = 0
2 * 0 = 1 * 0
Divide both the sides by 0 to get
2=1.
This is the actual error committed in the video, For sure. Because X = Y is the primary assumption. So X² = X.Y goes 0=0. So this is mathematically wrong because we cant divide anything by 0. Hope this answers the mistake.
JerryVikram 2 years ago 2
immortalnoob is right this guy cant factorise.
Preditor505 2 years ago
this guy cannot factorise.Check step 4 again and you wil see that he could take an extra x out of the brackets on both sides
immortalnoob 2 years ago
There is no mistake. Only in the final conclusion. Because X^2- X.Y will be always zero because X=Y. And 2 times 0 it´s equal to 1 times 0. This problem don´t have the solution of 2=1 but of 2/1=0/0 which is an indetermination, in this case any X you chose wil be a solution.
portuguesnanet 2 years ago
yaa
gauravrp2003 2 years ago
we know, since x=y, that x squared - y equals zero...no dividing by zero! It's not allowed. Thus, the error.
p.s. I love your LOST videos...way better than Seanie B, because you upload them faster and just give us the good stuff, not a long boring recap of every detail!
jesuisdeutah 2 years ago
youre a complete retard..
you are saying that x squared - y =0
lets say both x and y (because they are equal) are 5
25-5 doesnt equal 0 it equals 20
i dont know the problem with the equation in the video, but i know there is definitely a major flaw in your crappy logic
now i am not usually this rude, but you pissed me off about your comment on seanie b's videos. he makes such in depth recaps because some of his vieweres dont want to hear irrelevant topics lik james puts in his vid
doctorB92 2 years ago
That was to me?
It´s not X^2-Y=0
It's X^2-X.Y=0
You need to go again to school.
I don´t know if someone understood what you were trying to say with Seanie B videos...
portuguesnanet 2 years ago
wasnt talking to you dickweed..
doctorB92 2 years ago
doctorB92, Thank you for catching my error. I am embarassed that I made such a simple mistake. Here, I have since fixed the mistake:
we know, since x=y, that x squared - xy is essentially x squared - x squared, which equals zero...no dividing by zero! It's not allowed. Thus, the error.
p.s. I love your LOST videos (No offense is meant toward Seanie B or any of his followers.)
jesuisdeutah 2 years ago
sorry bout my rude reply, but i just got finished replying to someone who left a gay ass comment on my channel
doctorB92 2 years ago
This has been flagged as spam show
youre a complete retard..
you are saying that x squared - y =0
lets say both x and y (because they are equal) are 5
25-5 doesnt equal 0 it equals 20
i dont know the problem with the equation in the video, but i know there is definitely a major flaw in your crappy logic
now i am not usually this rude, but you pissed me off about your comment on seanie b's videos. he makes such in depth recaps because some of his vieweres dont want to hear irrelevant topics lik james puts in his vid
doctorB92 2 years ago
This has been flagged as spam show
That was to me?
It´s not X^2-Y=0
It's X^2-X.Y=0
You need to go again to school.
I don´t know if someone understood what you were trying to say with Seanie B videos...
portuguesnanet 2 years ago
this is all based on the assumption that x=y. He begins with x=y and adds and multiplies variables to both sides of that equation and eventually comes up with 2=1. Unfortunately, x does not = y and that is the error.
nthnthebsebllplr 2 years ago
"Unfortunately, x does not = y and that is the error. "
That is not the error, if he assumes that x=y, than x=y.
viharsarok 2 years ago
1/0=2/0
doesnot mean 1=2
ok dude
gauravrp2003 3 years ago
it s not 1/0=2/0 it s 1/1 = 2/1 !!
Alubrab 3 years ago
you're wrong 1/1 is a whole 2/1 is half a whole you're saying 1= 0.5 which is incorrect
wriddler 2 years ago
Comment removed
gauravrp2003 3 years ago
my mistake
but thats not trrue either
1X0 = 2X0
does not mean
1 = 2
because x2 - xy = 0
check that
gauravrp2003 3 years ago
You are quite fun to read 1x0=0=2x0=nx0
elnetini 2 years ago
a one legged man cannot stand on his head
0/1 not possible
SGWyoshi 3 years ago
Zero divided for 1 person... Person gets zero apples :o) So your answer is zero.
elnetini 2 years ago
lol to tell you the truth, i didnt watch the whole thing before, but just guessed because i assumed it was the same question
the real answer is that x is not equal to y, so xsquared is not equal to xy
SGWyoshi 2 years ago
I'll admit you got me to think though
SGWyoshi 2 years ago
Oh SHI-
rauron9 3 years ago
I know the Solution and the wrong thing.But i don t say it. Do not be jerks. Leave them to find the solution alone...
manosgun1994 3 years ago
you cant divide by 0. yay!
madnezz987 3 years ago
Wouldn't you think it's a huge waste of time just to prove that 1 = 2?
VitalSigns1 3 years ago
the 0/0 indeterminacy. Actually you guys are all dumb. It's the assumption that 0/0 is equal to any one number that's wrong. 0/0 is effectively equal to all numbers(including 2). The problem is that you assumed that it is only equal to 1. Since x=y, then x2-xy/x2-xy is 0/0. However, this does not mean that x2-xy/x2-xy is equal to 1. The typical explanation is that you can't divide by zero. You can; you just can't assume that this 0/0 is equal to one.
Drakeman8 3 years ago
Ironically, all the explanations on this page are wrong. 1. You can divide by squares accurately. 2. This is not a proof of 0=0. It is a proof of 0/0 = any number. 3. x and y don't have to be equal to zero. x2 - xy has to be equal to zero. Which is shown in the beginning by the assumption x=y. 4. You can, in fact, divide by zero. The problem is when you assume that x/0 is equal to some specific number. When x does not equal 0, x/0 is equal to + or -infinity. When x=0, x/0 equals any number.
Drakeman8 3 years ago
Division by zero is undefined...It is not any number or +,- infinity.
If you are taking a limit then that is a different problem. There are no limits being taken here.
ZR666 3 years ago 2
Comment removed
Drakeman8 3 years ago
Actually, it is possible to divide by zero. In many contexts, it is important to recognize this fact. 0/0 is the classical mathematical exploration called the indeterminacy, which I explained below. In other cases, like some aspects of quantum physics, it is important to recognize that any number divided by zero is infinity. I understand why you may shrug off the concept and simply decide that you cannot divide by zero. But that is an unfounded and incorrect generalization.
Drakeman8 3 years ago
No it is not. It is undefined. Only when you are taking limits is it an indeterminate form
ZR666 3 years ago 2
The video is about arithmetic. The real numbers are a field. Division by zero is undefined in a field.
ZR666 3 years ago 7
I guess that is a fair enough claim. However, it is necessary in many fields beyond simple arithmetic, making it an important philosophical point that it can be done. Although you are correct that it is usually done in the context of some limit, when used in many physics-based applications, it is used outside the context of limits as well. For most mathematical purposes we assume that it is undefined, however doing so is mainly just hair splitting as a result of it's unnecessary results.
Drakeman8 3 years ago
For instance, in a field if we assume division by zero to have a result, it must not only be + infinity but also - infinity. This is extraneous in most broad math contexts. However, when dealing with gravitational singularities, it becomes necessary to consider x/0 an appropriate maneuver.
Drakeman8 3 years ago
step 5
you can cancel the square by roots
if you dont understand then im not bother to describe
Th0usandMaster 3 years ago
dont cancel square by divide
cancel square by roots ONLY
Th0usandMaster 3 years ago
The proof I've provided in my last comment cannot be denied. As you started with assumption that X=Y so in the whole process we can use both of them at each others place. And when u do that in step 4 both sides go to zero. It actually proves mathematical fact that 0=0 not 2=1
AusPakWoman 3 years ago
Step 4: 2(X2-XY)=(X2-XY) (Read X2 as X square) As X=Y according to our fist assumtion,
So 2(X2-X2)=(X2-X2)
or 2*0=0
or 0=0
Thats what it's all about. In step 4 its just like both sides r multiplied by zero and he divides both sides by zero to eliminate it which is not possible.
AusPakWoman 3 years ago
Step 5 is wrong!!! It is impossible to divide by 0. Before you post any more proofs you should make sure they are correct!!
sunny8792remote 3 years ago
Wow. Someone doesn't listen to directions. Read the side box next time or watch the video until you hear my disclaimer saying it's incorrect.
mrjames113083 3 years ago
dood that's so cool ur awesome
iCeSk8uRFoShO 3 years ago
the only way 2(X2-XY)=(X2-XY) can be true is if X and Y equals zero....
that would make 2(0)=(0) or 0=0
NOT 2=1
I win....
LarryTheRubixCubeGuy 3 years ago
nooo ur so stupid it equals 1 i showed this to my math teacher its correct
iCeSk8uRFoShO 3 years ago
pfft lame... chuck norris could divide by zero >.>(awesome video tho) =)
YourSexyEnemy 3 years ago
the step when you divided by
(x^2-xy) can't be done because
you are dividing by zero.
(x^2-xy)=0 since we assumed
that x=y; therefore 2 is not
really equal to 1.
09harrisa 3 years ago
right.
rolo1382 3 years ago
I know an even better proof! 2=0!!!
Given a=1, b=1
Thus a+b=2, and a^2+b^2=a+b
Substitute, and get a^2+b^2=2
Factor to get (a+b)(a-b)=2
Plug in the original numbers, (1+1)(1-1)=2
Simplify, (2)(0)=2
Multiply, and you get 0=2
I CAN'T FIND THE ILLOGIC!!! WHERE IS IT???
aMinotaursJourney 3 years ago
a^2+b^2 does not factor into (a+b)(a-b), you would need to factor a^2-b^2.
Shade64 3 years ago
All you have to do is substitute a number for x.
2(x^2-xy)=x^2-xy ... substitute "x=3, y=3"
2(3^2-3*3)=3^2-3*3
2(9-9)=9-9
2(0)=0
0=0
Since you divided by zero, it screwed up your maths. You're not allowed to do that.
LanceTheBlueKnight 3 years ago
do you think people are so stupid?
misterknuddelfeck 3 years ago
when it comes to math...the average person kind of is.
mrjames113083 3 years ago
O, forgot
Unless you follow the concepts of transreal arithmetic you can't divide by zero.
But if you do follow transreal arithmetic than it equals a form of nullity and than the equation still doesn't evaluate to 1=2
FeinArtFilms 3 years ago