Hey I have a question.. lets say you are given a point off the graph of the function and your are given an function, lets say x^2 how can you find the point the tangent line goes through on the graph y = x^2 and the point given that is not on the function y = x^2?
What would you do if you were only given the equation for the curve and some arbitrary point through which the tangent line will pass, not on the curve? For example, suppose you had a function f(x)=x^2+x, and you wanted to know the equations for the tangent lines passing through (2, -3)?
@LandonHobbs Actually I think you have to take the derivative of the function and equate it to the point slope form of the point given (2, -3)... something along the lines of that.
Akash makes you do his homework :p great videos by the way, I'm currently preparing for my Calculus 1 end of year examination and have been using a lot of your videos for review.
I'm confuse. My teacher told me to use y-yo=m(x-xo)
intermaniax1 1 week ago
i recognize that graph website!!!
ibrahim795 2 weeks ago
Thanks...
helix4811 3 weeks ago
and now the tangent line at a circle ! :s
TheParilicious 2 months ago
Every time I watch one of your videos I get 1% less stressed about my calculus final.
TheWuFinancial 2 months ago
you're bloody legend mate, i'm struggling with this stuff in class and you're probably the only person that i get. cheers man.
iamhoosi 3 months ago
It sounds like Chad coL.Minigun from SC2
wakeboy45 4 months ago
I felt like I was being yelled at in the first 3 seconds of the video haha
kx32ta1 10 months ago 22
thank you, akash.
idster7 1 year ago
Hey I have a question.. lets say you are given a point off the graph of the function and your are given an function, lets say x^2 how can you find the point the tangent line goes through on the graph y = x^2 and the point given that is not on the function y = x^2?
Morelloo1 1 year ago
What would you do if you were only given the equation for the curve and some arbitrary point through which the tangent line will pass, not on the curve? For example, suppose you had a function f(x)=x^2+x, and you wanted to know the equations for the tangent lines passing through (2, -3)?
LandonHobbs 1 year ago
@LandonHobbs Actually I think you have to take the derivative of the function and equate it to the point slope form of the point given (2, -3)... something along the lines of that.
Morelloo1 1 year ago
lol at the beginning it sounds like he's yelling. I got all skeerd D:
SaraNicolette 1 year ago 2
Sal Sal Sal.....Thanks a Ton....ur the greatest tutor in dz universe....God Bless u!!
saimohan007 1 year ago
Akash makes you do his homework :p great videos by the way, I'm currently preparing for my Calculus 1 end of year examination and have been using a lot of your videos for review.
xpicardx 1 year ago 2
lol im in college trying to learn this, but watching this once helped so much
walikai 2 years ago 5
shouldn't this video come MUCH earlier in the playlist, before the polynomial approximations and integration?
gobberpooper 2 years ago 16
does anyone know which video is the one that explains how to get the integral of an equation that cant be integrated? Its something field.
veteran25 2 years ago
Thanks Aakash.
philjc54 2 years ago
Pretty exciting stuff
marcusjhung 2 years ago
THANK YOU SO MUCH. This video REALLY helped! I would have been struggling without you! What a great service you've done.
snusmumriken232 2 years ago
i wish i had known about this video sooner
Alaunos9124 2 years ago
Great vid., Sal! I love how you are so fascinated every time the derivative of y=e^x comes up.
brco2003 3 years ago 5
Does anyone know if this dude made that graphing utility or if it is available somewhere?
hs1white 3 years ago
the graphing utility was found on a website..umm..check his video 2 videos before this..he tells the website
darkfighte 3 years ago 2
For those who understand it, it is really helpful!!! :D
donald4444 3 years ago