You have to take the subnet (172.16.2.16) last number and add the binary number 1111, which will give you 31. Remember he added up all the host numbers to get 1111.
I have never used the logical and process. This gave me some serious "AHA!" moments in learning subnet tricks. I HATE doing stuff on paper but this gave me some VERY useful tips on converting and doing addressing. THANK YOU! Great stuff.
ur magic-number trick.. works on all IP classes ?! if it does.. do we always start the table with 192 on the right and start jumping depending on the subtraction? thank you
Hey John, Its really nice the way to teach. I have attended CCNA 1 virtual classes in Italy, to be honest... did nt get much. I am doing well with ur online coaching. Looking forward to hear some carrier guidence from you. i would like join Oil and Gas sector with Networking. I used to work in Logistics dept.
With that small mistake and the "and" rule applied everything is ok. The final results are ok :D Thank you for those great videos ! Maybe a bit of VLSM in the future???
I've watch all ur videos and they are the best in terms of the actual steps involve in IPv4 Subnetting and I,m now able to answer all if not most of the Question I’ve found on the Net so far..Ive just started CCNA and I was unable to follow my tutor when it came to Logical AND.Ur videos have made everything so clear and informative as if u assume that ur viewers are at the beginner stageThanks a lot.
I've watch all ur videos and they are the best in terms of the actual steps involve in IPv4 Subnetting and I,m now able to answer all if not most of the Question I’ve found on the Net so far..Ive just started CCNA and I was unable to follow my tutor when it came to Logical AND.Ur videos have made everything so clear and informative as if u assume that ur viewers are at the beginner stageThanks a lot.
To MrHeyom: Yes, I can see that now, hadn't even noticed, but some people in here are also attacking that the subnet mask should have been x.x.x.60 instead of x.x.x.56, that is why I posted the comment.
Great video, that's amazing how something so complicated can be made so simple, you are an excellent tutor, we want more and thanks
the last octet of the address is 00111100 and the last octet of the subnet mask is 11111000 then you AND the and the final result is 00111000 which is 56 my friend
the mistake was small. (when you converted the 60 to binary number...the 1 was left out of the 4 digit). other than that the video is excellent. great job
I believe is valid to make mistakes... that allow us to see who just watch the videos to criticize trying to be smart without bringing something positive. Take care :)
I'm just about to start my CCNA training, i found this video (and all the others I watched so far) to be excellent and you make it easy to understand by breaking it down !
O.K., so 60 should be written 00111100. But even if you ANDed it as 00111000 it still would've given you a 0 as the result for those bits because the value in the Subnet was 0, right?
There're mistakes in the video examplo for subnetting bacause .60 in binary is not 11100 is 111100 so the subnetwork portion address is 201.200.10.111000 and the broadcast is 201.200.10.59 or 201.200.10.00111011
I think you also have a mistake. If you are going to AND [60]00111100 & [248]11111000 you will arrive with the answer of [56]00111000 for the subnet, [63]00111111 for the broadcast address and 203.200.10.57 - 203.200.10.62 of host range.
Great job John. I watched the 5 parts as a refresher and they were great. Please post some more videos. You're videos are very easy to follow and understand.
Thank you Mr. John Mills, PLEASE MORE MORE MORE. I enjoy learning from you. I wish my teacher knew asmuch as you. I'am very intrested in more knowledge. Thank you very much Mr. Mills I appreciate it tremendously!
This is good, I think you explain this better than my teacher. Might be the fact that he uses a whiteboard instead of special effects XD. This is good
Isn`t there a mistake in the video ? When he is doing the logical end he gives for the IP X.X.X.60 a 00111000 for the last octet but it has to be a 00111100. Let me know when I am wrong. The rest is just perfect. Thx a lot
nono its Ok. the video is still very helpfull. Everyone that is intereseted in this topic will find out himself. So its a good test for everyone ;) Thx again from germany ;)
Isn`t there a mistake in the video ? When he is doing the logical end he gives for the IP X.X.X.60 a 00111000 for the last octet but it has to be a 00111100. Let me know when I am wrong. The rest is just perfect.
Presented in clear, simple and and logical manner. Really good. Just what is needed to understand simple IP in the working world. In addition to the well organized content, i like John 's clear pronunciation, guess that comes with his Englishman accent. Keep it coming and THANK YOU JOHN! Well Done!
hi robman78, i want a lil help from you. i am thinking for doing CCNA, but i don't know where to start, how hard is it? i don't know much about Networking, just can manage little network, (Lan) , but don't know much about networking. so can u please guide me that where to start. i will appreciate your help
For those who might be confused: During the exercise John states that 60 equals 111000. It really doesn't matter since the mask doesn't envolve anything beyond the final 1. But for those of you who might be confused 60 equals 111100. After the and operation you end with 111000 (56).
Great vids! I watched them all! Good refresher! Can tell your CCIE!
I did not get that part the first time. The missing 1 made all the difference.
I'm beginning to thing like a computer -_-
snapsh00ter 1 week ago
Wish i should read the comments first ,it took me alot time thinking of how the binary of 60 is with only three 1's its "00111100"
dattuj 1 month ago
very nice of you t help everyone . thanks
jellybean2626 1 month ago in playlist More videos from panchotraining
Define the terms to real time experience like in DSL?
munawar1989 1 month ago
Where did you get the broadcast address of 172.16.2.31 where did the 31 came from .. Kindly explain thank you.
tacolitz 3 months ago
You have to take the subnet (172.16.2.16) last number and add the binary number 1111, which will give you 31. Remember he added up all the host numbers to get 1111.
eric24g 1 month ago
I have never used the logical and process. This gave me some serious "AHA!" moments in learning subnet tricks. I HATE doing stuff on paper but this gave me some VERY useful tips on converting and doing addressing. THANK YOU! Great stuff.
koihoshi 4 months ago
i have a question plz!
ur magic-number trick.. works on all IP classes ?! if it does.. do we always start the table with 192 on the right and start jumping depending on the subtraction? thank you
khellozme 5 months ago
Nice job on parts 1-5. I like the exercises at the end as it helps yo understand what you just taught.
Mrtpberry 6 months ago
Wow, I liked your discussions John. thank you for this.
kawukileonard 6 months ago
Wow, I liked your discussions John.
kawukileonard 6 months ago
GRETA IDEA
lovdeeppahuja 8 months ago
wow...this video really opened up my understanding, thank you very much for this :)
khilla 8 months ago
PANCO you are good thaks.
electromata 8 months ago
Hey John, Its really nice the way to teach. I have attended CCNA 1 virtual classes in Italy, to be honest... did nt get much. I am doing well with ur online coaching. Looking forward to hear some carrier guidence from you. i would like join Oil and Gas sector with Networking. I used to work in Logistics dept.
Regards
Amit
gowildamit 8 months ago
Thanks John, your videos are awesome!!!
So Clear and to the Point! =)
mocha4life78 9 months ago
tnx :) alott ...
777ghu 9 months ago
great work. finally i learned something clear and solid.
VictorButny 9 months ago
.60 is 00111100. you put 00111000
perezjorgejr 9 months ago
Great video!! Keep them coming.
sreid70 9 months ago
hehê_î_fèêl_sÒ_lONElý_t0DÅy
SupaioMillieay853 9 months ago
Very helpful presentation - thank you for posting. Thumbs up!
Kage1111 11 months ago
With that small mistake and the "and" rule applied everything is ok. The final results are ok :D Thank you for those great videos ! Maybe a bit of VLSM in the future???
johnnycd4EVER 11 months ago
fantastic, simple explanation. thank you.
jmtahart 11 months ago
Thanks for the videos. They are a big help!
mteeheet56 1 year ago
Great tutorial! I hope to see more in the future.
miichaelcannon 1 year ago
Thank You for your presentation...
.
Pakistan, Karachi...
looserofssuet 1 year ago
Mr john Mills,many thank you and respect for your excellent work!
greece
dkniles1 1 year ago
Mr john Mills,many thank you and respect for your excellent work!
greece
dkniles1 1 year ago
great video. I had to watch few times to understand this. this will help me with icnd2 exam.thanks a lot
rcstar07 1 year ago
Please post more videos. Gosh I understand this a lot better than my classes. Huh! John u r my savior! Please post more videos.
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daciaheslinyfh 1 year ago
binary adress of 60 is 00111100 anyways the subnet is 00111000 ie 56 :)
crazzychap 1 year ago
Thanks! This really clarified subnetting for me rather well. Now, for VLAN...
jdwilkins8 1 year ago
This has been flagged as spam show
We hit it off so well after another visit busizz4me.info
shamekawood 1 year ago
I think I get now. If I watch it everyday maybe It'll stick
tanisha706 1 year ago
@tanisha706 Just maybe...
MiggyCW 1 year ago
explained it much better than my teacher :D thanks
thelixir715 1 year ago
I get it! Finally, thanks so much.
Pacman2608 1 year ago
Very good. Have a test tomorrow. Thx.
alanes335 1 year ago
Great video...keep up the good work mr.pancho...i watched all parts and now i understand ip addressing and subnet masking..clear things up big time
MsMrbighorn 1 year ago
These are very nice talks on basic IP addressing.
jed1nok 1 year ago
This good man ! keep up...very helpful and clear despite the quality of display
linkin0007 1 year ago
really very helpful and interesting!!
sujithk84 1 year ago
greatvids much respect from new zealand. z.
tomass123 1 year ago
I've watch all ur videos and they are the best in terms of the actual steps involve in IPv4 Subnetting and I,m now able to answer all if not most of the Question I’ve found on the Net so far..Ive just started CCNA and I was unable to follow my tutor when it came to Logical AND.Ur videos have made everything so clear and informative as if u assume that ur viewers are at the beginner stageThanks a lot.
masg0478 1 year ago
I've watch all ur videos and they are the best in terms of the actual steps involve in IPv4 Subnetting and I,m now able to answer all if not most of the Question I’ve found on the Net so far..Ive just started CCNA and I was unable to follow my tutor when it came to Logical AND.Ur videos have made everything so clear and informative as if u assume that ur viewers are at the beginner stageThanks a lot.
masg0478 1 year ago
thanks for the upload .. great video
mjben0407 1 year ago
Great Videos. I can say that i really learned a good "bit" of information. Thanks! I hope you continue to make videos on this subject.
TheKyleBinniShow 1 year ago
I thought I was going mental for a second. "That doesnt add up!" ok I feel better lol
Anthem127 1 year ago
little mistake, but ok!
rafpelegri 1 year ago
thank you so much
richiexp2 1 year ago
Brilliant Video , keep it up :)
badr535 1 year ago
At 5:45 there seems to be a minor error. If the address is .60, then shouldn't the binary of that be 00111100, not 00111000?
sbowesuk 1 year ago
great very intresting.... easy to understand...Good teaching..thanks a lot...
msjaga21 1 year ago
You are great I worked it out I managed to work it out the first time. What a great teacher.
BROADBANDPCCARE 2 years ago
thanx thanx thanx thanx a lot..:-)
THEMaGaR 2 years ago
Sorry correction, I meant to say subnet portion not subnet mask. lol
damnu22 2 years ago
To MrHeyom: Yes, I can see that now, hadn't even noticed, but some people in here are also attacking that the subnet mask should have been x.x.x.60 instead of x.x.x.56, that is why I posted the comment.
Great video, that's amazing how something so complicated can be made so simple, you are an excellent tutor, we want more and thanks
damnu22 2 years ago 2
A mistake:
From the address 203.200.10.60
When we want to make a binary for 60*, it should be 00111100
He said 00111000 the = is 56, therefore as in 00111100 the = is 60*
Thank you so much sir.
MrHeyom 2 years ago
you just prove that you haven't watched closely.
the last octet of the address is 00111100 and the last octet of the subnet mask is 11111000 then you AND the and the final result is 00111000 which is 56 my friend
damnu22 2 years ago
yea correct a mistake as below 00111100 (32+16+8+4=60) , good vid though great fresher.
Battleneter 2 years ago
a little mistake
for the 60 in binary it should be 00111100 (32+16+8+4=60)
cronosmachine 2 years ago 14
@cronosmachine dose it effect the whole answer? i mean they're all wrong ??
iktt 9 months ago
@iktt Calculating the subnet ip, the answer is NO; doesn't affect the final result.
VictorButny 9 months ago
the right variant is the following:
subnet address: 203.200.10.60
broadcast address:203.200.10.63
host range: 203.200.10.61 - 203.200.10.62 .
aztek1934 2 years ago
@aztek1934
It does not affect the result since logical AND between the Subnet Mask and the Address causes the result to remain 56.
neeroro 1 year ago
thank you for this video...,,it's so good
jfm2279 2 years ago
Whoooo Hoooo - the light just came on!
Thank you & keep-um-commin
trav1so 2 years ago
gr8 tutorial..now I will ace my test ;)
bhanuzxc 2 years ago
Brilliant Video , just a little mistake
for the 60 in binary it should be 00111100 (32+16+8+4=60) even if doesnt influence the result.
Thanks for the video.
nbayiha 2 years ago 18
@nbayiha got stuck there for a moment as well, but as you've noted 1+0 = 0+0
in 'AND'-speak....that said, this video series is a great review
AJtheory 1 month ago
thanks easy to understand
ginoscar 2 years ago
Thanks and was very informative. Thanks Again
tonybahrain 2 years ago
Best subnetting class by a long shot. And all in about an hour. Very appreciated! I can go to sleep now!
zizyphus99 2 years ago
32 + 16 + 8 != 60
thablackmarkit 2 years ago
You forgot to add the host part.
32+16+8+4+2+1 = 63
widgeo 2 years ago
dude..thats 56...lol..
surrealpast 2 years ago
Jesus christ, the CCIE is wrong.
thablackmarkit 2 years ago
really nice and well explained
sujitjacob 2 years ago
Thanks very much Sir. Very informative and well explained.
53nat0r 2 years ago
Brilliant Video..Spot on and very informative..96%
shalobis 2 years ago
nice tutorial
love to watch
petetikesava 2 years ago
Brilliant videos explained everything again in plain English :)
I also spotted the mistake lol
JIMIJIM 2 years ago
Great videos!
ProgramJava 2 years ago 2
Very informative. I am trying to master this skill and this video is a great help. Thanks!!
allenn3232 2 years ago
the mistake was small. (when you converted the 60 to binary number...the 1 was left out of the 4 digit). other than that the video is excellent. great job
jmainewill 2 years ago 3
Thank you for this wonderful presentation. I had been struggling with subnetting for a while but you have made it quite simple. Thanks again.
rikstar81 2 years ago
Awsome tutorial's, loving them...You did arse me up with the binary calculation of 60 as it was plain wrong, you showed a binary value of 56 ;)
flapshot 2 years ago
u are a good Guru
Badrol007 2 years ago
great tutorials.. all the parts made the concept very clear. Thank you.
devosky 2 years ago
u did a bit wrong in this video
dont make any mistakes next time
andhraindia1 2 years ago
I believe is valid to make mistakes... that allow us to see who just watch the videos to criticize trying to be smart without bringing something positive. Take care :)
ClodomiroPerez1 2 years ago
There are one mistake.
60 = 00111100
in the video 60 = 00111000 witch is 56
:)
IvanRadev 2 years ago 2
i noticed that too
chernobila 2 years ago
I don't see any mistake. I think because you people don't understand what's going on here that's why you think there's a mistake.
ssthao 2 years ago
the mistake is in the converting 60 Decimal to Binary there is one missing at 4 !
konfetti002 2 years ago 3
Lol it's you who doesn't understand whats going on here.
surrealpast 2 years ago
Fantastic learning videos!
drakezen 2 years ago
Watched 1-5. Extremely well described!
ericsyn 2 years ago 2
FUKIN LOVLEY !! CHEERZ
BEBOCLIPS 3 years ago
Nice one, Thanks..
706brotherhood 3 years ago
I'm just about to start my CCNA training, i found this video (and all the others I watched so far) to be excellent and you make it easy to understand by breaking it down !
Thank you !
kdf666 3 years ago
be carefull john not to make "too many" mistakes.
but, i would have you as my tutor. you have a talent to put your message across.
i found your videos quite usefull in understanding ip adressing.
thanks. do more please!
tbmtbm 3 years ago 3
He did make a mistake when he converted 60 to binary. he should have turned on binary 4.
The result would have been the same thou. Great videos. I watched all of them.
RBaggio25 3 years ago 2
How did he get 56 when he converted the binary numbers back to decimals I got 60
Yakandke 3 years ago
O.K., so 60 should be written 00111100. But even if you ANDed it as 00111000 it still would've given you a 0 as the result for those bits because the value in the Subnet was 0, right?
chicks123 3 years ago
Correct
scivi92 3 years ago
Cool.
chicks123 3 years ago
He did 60 wrong
It should be 32+16+8+6 (00111100) not 00111000
????
sdfghjkl08 3 years ago
watched 5 vids - gr8 work cheers!!!
sagay 3 years ago
Mr. John Mills I really appreciate your video! Thank You!
NetworkAmateur 3 years ago
Great video, very well structured. Pls show some CIDR's thanks!
mrshaz 3 years ago
John,
I watched 5 in a row -
great presentation,
thanks for your time
and posting these videos
-jj
javajohnson 3 years ago
There're mistakes in the video examplo for subnetting bacause .60 in binary is not 11100 is 111100 so the subnetwork portion address is 201.200.10.111000 and the broadcast is 201.200.10.59 or 201.200.10.00111011
besides the host range changes too, to .57-.58
WilsonCely 3 years ago
I think you also have a mistake. If you are going to AND [60]00111100 & [248]11111000 you will arrive with the answer of [56]00111000 for the subnet, [63]00111111 for the broadcast address and 203.200.10.57 - 203.200.10.62 of host range.
NetworkAmateur 3 years ago
great video series..great job John.. more vid please
adivok 3 years ago
Great job John. I watched the 5 parts as a refresher and they were great. Please post some more videos. You're videos are very easy to follow and understand.
gigabitethernet 3 years ago
Very well done, thank you, I will be subscribing to hopefully learn more!
hankmap 3 years ago
thanks for the educational info...I would love to see more of your videos..thank you !!!
tenzinpalden 4 years ago
Thank you Mr. John Mills, PLEASE MORE MORE MORE. I enjoy learning from you. I wish my teacher knew asmuch as you. I'am very intrested in more knowledge. Thank you very much Mr. Mills I appreciate it tremendously!
DATBOYGOTHEAT 4 years ago
Cisco Tricks pleasssssssssssssssseeeeeeeeeeeeee
bamidele112 4 years ago
This is good, I think you explain this better than my teacher. Might be the fact that he uses a whiteboard instead of special effects XD. This is good
Ydontugetwow 4 years ago
Great video, I've already taken this course, but rewatching this video refreshes a lot of topics and makes ccna 3 a bit easier.
Y0uEnj0yMyself 4 years ago
Brill Thanks if you can post your Cisco tricks that would be great!
craiglee10 4 years ago
Isn`t there a mistake in the video ? When he is doing the logical end he gives for the IP X.X.X.60 a 00111000 for the last octet but it has to be a 00111100. Let me know when I am wrong. The rest is just perfect. Thx a lot
HNXDINOZZO 4 years ago 8
Apologies, you are quite right! I will try to ammend this video.
John
panchotraining 4 years ago
nono its Ok. the video is still very helpfull. Everyone that is intereseted in this topic will find out himself. So its a good test for everyone ;) Thx again from germany ;)
HNXDINOZZO 4 years ago
"will find out himself."
silly silly
us women find it helpful to
guys are not the only ones interested
and thank you john! great videos
fuzzy002 4 years ago
You 're right i noticed that too, thanks for the info.
DirtyJayx 4 years ago
Isn`t there a mistake in the video ? When he is doing the logical end he gives for the IP X.X.X.60 a 00111000 for the last octet but it has to be a 00111100. Let me know when I am wrong. The rest is just perfect.
HNXDINOZZO 4 years ago
As a recent college graduate in IT, I have to thank you for your great YouTube videos on the CCNA.
Please create more of these as the videos explain the subject better than most the Cisco's curriculum does.
girenzabi 4 years ago
Thank you John, loved the CCNA course I attended that you taught recently, and the videos are a brilliant refresher in preperation for the exams.
Godders112 4 years ago
This is Awesome, I'm loving it
MK4bora28l 4 years ago
Presented in clear, simple and and logical manner. Really good. Just what is needed to understand simple IP in the working world. In addition to the well organized content, i like John 's clear pronunciation, guess that comes with his Englishman accent. Keep it coming and THANK YOU JOHN! Well Done!
goowealth 4 years ago
YOU ARE WELLCOM
abozarad0 2 months ago
the bomb! lovin it.
pjdarmis 4 years ago
These are really good!! Cuts through the bull and gets right to it. Good job, John.
Diabolik771 4 years ago
Thanks for the help. I am currently studying for my CCNA and this helps alot. Would like to see more CISCO tricks
Thanks
robman78 4 years ago 2
hi robman78, i want a lil help from you. i am thinking for doing CCNA, but i don't know where to start, how hard is it? i don't know much about Networking, just can manage little network, (Lan) , but don't know much about networking. so can u please guide me that where to start. i will appreciate your help
dxbtalal 4 years ago
Cisco has a complete CCNA curriculum they offer on the subject. It's a lot of work, and requires much dedication and love of all things networking.
In the end you get the certification if you can past the HARD test.
girenzabi 4 years ago
For those who might be confused: During the exercise John states that 60 equals 111000. It really doesn't matter since the mask doesn't envolve anything beyond the final 1. But for those of you who might be confused 60 equals 111100. After the and operation you end with 111000 (56).
Great vids! I watched them all! Good refresher! Can tell your CCIE!
nimrodsixty9 4 years ago 2
Sorry, never could count in binary
panchotraining 4 years ago
Thanks alot for these vids, i'm going to start studying for the ccna soon. This gives me the heads up of what to expect.
Any chance you could do some videos about the osi model ?
HorraceUK 4 years ago 2