Derivatives of Inverses I

[hadd93]

Couldn't you have pluged in f(x) when you had the inverse g(X) at like 2:32 and plug in 3 after that to make it 1/(3(x^3+x+1)+1)? Instead of doing all that math and critical thinking I thought that might be easier but I don't know if you can do that and still get the answer

[xSebas6089x]

thank you !!! also this vid looks like it was taken in the 70's lol, hmm...when you derivated the inverse with respect to X , why did you end up with 1 divided by the answer.

[calctube]

@xSebas6089x You mean around 2:10? Yeah that was REALLY unclear. I just did the algebra quickly. I took the 2nd line:

1=3y²y' + y', factored out the y' on the right, and then divided.