Thank you so much Patrick! You've been a great help throughout the semester and now as I'm reviewing for my family. Your videos are beautiful; your explanations are clear and easy to understand. If you ever write a textbook or manual let us know as I'd love to use that to supplement my classes!!
Awesome videos! But I just had a question, when you are finding the inflection points and you use a number that's less than one, lets say -1, shouldn't that be 2((-1)-3)=-8/(-1)^4)=-8? So you get a concave down? If not please explain because I don't get it otherwise!
How do I know y=0 as a horizontal asymptote only applies on (-infinity,0)U(1,infinity)? ie. the curve crosses y=0 at (1,0) but can't cross it anywhere else... I guess I don't understand how it is an asymptote when the curve crosses it.
You said your final graph would be wrong, but isn't it actually correct? Your mistake in arithmetic was of course wrong, but your graph is still right from what I can tell.
when you did the concavity, on the left side of 0, isn't its suppose to be concave down instead of concave up because when u plug in -1 into the equation, the answer will be -8. At least thats what I think it should be.
I got a test in the next few hours on this. Though sucks because none of the functions I have to sketch are going to be as simple as this one. Same idea, yes, but more prone to stupid mistakes, YES! Good video.
by the way it wasnt a mistake, it's still concave up, since the denominator would also give a negative, so in the end you still get a positive, concave up.
The graph is actually correct. I used my graphing program to double check. Only the table that said that from negative infinity to 0 is concave up is wrong but you can see that he draw a concave down in that interval so it's all good.
For every exam so far i've used ur videos. I was considering dropping the course and changing majors till i found these. ur a life saver. Thank You so much!!!!
I dont understand when you did your second derivative and you used 3 in which aren't you suppose to use the critical #'s as ur intervals? I'm so confused.
Your graph still turned out correct even though you made that concavity error. when determining the concavity you did make an error saying it was concave up, but then during the process of sketching you corrected yourself saying it was concave down.
@starwarsfreakdood A function can cross a horizontal asymptote as long as it approaches said horizontal value as it goes to infinity, it cannot, however, ever cross a vertical asymptote.
I thought the concavity from negative infinity to 0 was concave up? But the graph is concave down from negative infinity to 0. Not that it will ever reach 0 but I thought it would look different based on the information.
hello, thank you for the video. I have a question, I am trying to obtain infexion points what should I do when in f I plug in the value that I obtained solving f '' and it results undefined? f(x)=f ' (X )= (-2x^2)+x+3) / (x+2) and f '' (x)= (-14(x+2)) / (x+2)^4 Does that mean that there are not inflexion points?
Question, u said there is a HA at 0, if that is the case there couldn't be any pts on the x-axis right? so how is it that we get an intercept at x=1? (I understand how we get that intercept, but it technically doesn't make sense).
yeah its almost correct.. at the right corner it should be down down like on the x axis sort of thing..
but still thank you for this, your doing a great thing for this world dude!! =P and trust me my mom always says.. be nice to the nerds.. becasue one day youll be working for one.. =D
dam thank god for ur videos.. my teacher is british and tries to be funny when he teaches... he says the same joke over and over again in class and the retard nerds laugh at it everytime...
I love you *3* very useful videos. I have a terrible prof this semester, he doesn't even know what he's doing, so this is a huuuuuuge help to clear things up :)
i think the graph has been corrected, this is what the graph should look like (the first part is concave down, decreasing) before he said it was concave up. Im pretty sure he made the correction already.
what does it mean when your criticals numbers from your first derivative are the same as the second derivative?i have a local minimum i found from the 1st der. but the same critical number showed up in the 2nd der.
yes, plug it into the original. after all, we are trying to find inflection points on f(x); the first and second derivative just help to tell us where to 'look' on f(x)!
So when you find the inflection number, you plug that into the ORIGINAL equation to find the y-coordinate of an inflection point, not the first derivative, right?
Thank you so much Patrick! You've been a great help throughout the semester and now as I'm reviewing for my family. Your videos are beautiful; your explanations are clear and easy to understand. If you ever write a textbook or manual let us know as I'd love to use that to supplement my classes!!
SynpaticInc 1 month ago
isn't the graph still right? that's concave down from infinity to 0
free1here 1 month ago
Awesome videos! But I just had a question, when you are finding the inflection points and you use a number that's less than one, lets say -1, shouldn't that be 2((-1)-3)=-8/(-1)^4)=-8? So you get a concave down? If not please explain because I don't get it otherwise!
parmi4i 1 month ago
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parmi4i 1 month ago
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parmi4i 1 month ago
you are the best! thank you!!!!
999m4em 1 month ago
How do I know y=0 as a horizontal asymptote only applies on (-infinity,0)U(1,infinity)? ie. the curve crosses y=0 at (1,0) but can't cross it anywhere else... I guess I don't understand how it is an asymptote when the curve crosses it.
physicistinthemaking 1 month ago
Hey can you recommend any studying techniques? Great videos!
jmartr34 1 month ago
@jmartr34 read, do problems, re-read, do more problems
patrickJMT 1 month ago 5
If your HA is 0 then why does your graph cross 0?
iiottoii 1 month ago
@iiottoii a graph can cross its horizontal asymptote
patrickJMT 1 month ago 3
i love you pat.
Khizzzzzy 2 months ago
thanks heaps man, my maths class is wayyy behind the other class and i had to catch up over the weekend. your vids helped heaps!
masterchief9064 2 months ago
The broken cap on his marker is driving my OCD self crazy!
BadAceBarker 3 months ago
You said your final graph would be wrong, but isn't it actually correct? Your mistake in arithmetic was of course wrong, but your graph is still right from what I can tell.
Cancer98765 6 months ago
=3
2:17
Got it ?!
:p
na9oooooooor 6 months ago
=3
:p
na9oooooooor 6 months ago
when you did the concavity, on the left side of 0, isn't its suppose to be concave down instead of concave up because when u plug in -1 into the equation, the answer will be -8. At least thats what I think it should be.
dhaval712 7 months ago
do porn
Crossoverzz 7 months ago
Your the best !!
Raymondlk 8 months ago
2((-1)-3) does not equal a positive number...
kforsyth31 8 months ago 3
Final Cal Exam 2mrw, now i'm READY xD !
bking0704 8 months ago
This has been flagged as spam show
isnt (negative infinity,0) supposed to be concave down? cuz the numerator is negative while the denominator is positive.
kpxflameboy 9 months ago
Comment removed
kpxflameboy 9 months ago
is the new video uploaded or not yet?
link me please
thanks in advance
and patrick i love you
MultiMoe91 9 months ago
If I get a 5 on my AP exam, it'll all be because of you.
EdBogie 9 months ago
Just so you know the correction dont show up on my iPhone. So for the 3 of us that watch these in public have that to worry about.
dghansen85 9 months ago
YOU.ARE.AMAZING.
billyo1989 9 months ago
You are extremely helpful!! thank you so much... you explain in a very simple way and not many can do that
2030587 9 months ago
THANK YOU THANK YOU THANK YOU!!!
missdillpickle 9 months ago
Am I the only one who was gonna see some awesome movie of some guy doing calculus and ending up with a ''sketch'' of a woman's curves? >.>;;
~Jkun~
Jkun 10 months ago
i have bent sharpies too : 0
skyfaze 10 months ago
I got a test in the next few hours on this. Though sucks because none of the functions I have to sketch are going to be as simple as this one. Same idea, yes, but more prone to stupid mistakes, YES! Good video.
Clipster15 10 months ago
hi, why is there no local min?
maxiswitty 10 months ago
i don't understand why 0 isn't an inflection point?
kevinwiz 10 months ago
@kevinwiz theres a VA at x=0 there can't be anything there.
vamosrogerfederer 10 months ago
by the way it wasnt a mistake, it's still concave up, since the denominator would also give a negative, so in the end you still get a positive, concave up.
eMCRutz 10 months ago
@eMCRutz Incorrect, because x^4 would make the denominator positive. Now if x was raised to an odd number, then it would give a negative value.
ZombieGadget 10 months ago
ur awesome!!!!!!!!!
Sylvanas17 11 months ago
hey patrick im from malaysia...great vids, i got a test tomorrow hope i can ace it from studying your vids......
fuarddy 11 months ago 15
@fuarddy good luck!!
patrickJMT 11 months ago 4
@fuarddy I am from Malaysia too.. in Multimedia university, Melaka.. I used to study from Patrick's video a lot!
alexspoy 7 months ago
I caught that mistake you pointed out, too :)
Great job. You're videos really help to clarify what I partially understand.
smartaleck05 11 months ago
The graph is actually correct. I used my graphing program to double check. Only the table that said that from negative infinity to 0 is concave up is wrong but you can see that he draw a concave down in that interval so it's all good.
PS. NEVER STOP DOING VIDEOS.
GeneralLee721 1 year ago
Dear Patrick, I think I love you now.
TheDude541 1 year ago
This has been flagged as spam show
this helped me soo much! thank youU!!!!!!
poohkah3 1 year ago
this helped me soo much! thank youU!!!!!!
poohkah3 1 year ago
im scared of cos and sine ones.
Morelloo1 1 year ago
i really wish this guy was aloud to post vids > 10 minutes.
mws123 1 year ago 5
@mws123 i can now do that. but i think shorter is better often times. people will not watch long videos (most people that is)
patrickJMT 1 year ago 6
@patrickJMT Yeah i know, there are these like hour long MIT videos with even more info but i see most people have no interest in watching them.
webmastertool 1 year ago
thanks so much.
can u do some more examples please
therab00 1 year ago 2
For every exam so far i've used ur videos. I was considering dropping the course and changing majors till i found these. ur a life saver. Thank You so much!!!!
iraqiya1991 1 year ago
Thank You So Much!!!! U R MY LIFESAVER!!!!!
btw: U teach way better than my prof.
1789Mikaela 1 year ago 2
I dont understand when you did your second derivative and you used 3 in which aren't you suppose to use the critical #'s as ur intervals? I'm so confused.
yukyisan 1 year ago
@yukyisan
the 3 is to get the zero for the numerator
etismyname 1 year ago
at the end how come the second line does not stop for the horizontal asymtote??
shahzebahmed1990 1 year ago
who else has a calc test 2mrw?
vicb0t 1 year ago 186
@vicb0t not me!
patrickJMT 1 year ago 26
@vicb0t I DO!
Jsebas289 1 year ago
@vicb0t
Me. :( Hate calculus. thank god for youtube!!only way im passing it. lol
iraqiya1991 1 year ago
@iraqiya1991 i dropped calc a few days ago cuz i didnt find his vids in time... :/
vicb0t 1 year ago
@vicb0t Mine is today :P
hondai 1 year ago
@vicb0t i have one in 30 min. skipped school to watch some youtube vids on calc
JSasRays 11 months ago
@JSasRays im retaking this shish!
vicb0t 11 months ago
@vicb0t LOL!! XD
Jenuvio 10 months ago
@vicb0t hell yeah, tomorrow- on a friday -_- i guess no fun fun fun fun for me lol
2030587 9 months ago
Your graph still turned out correct even though you made that concavity error. when determining the concavity you did make an error saying it was concave up, but then during the process of sketching you corrected yourself saying it was concave down.
blaze4404 1 year ago
This has been flagged as spam show
Ready to night party and meet naughty women **mworld5.info**
TarynViviana 1 year ago
Thanks for your help!!(:
what website can we find more or ur videos?!
MissKorky 1 year ago
@MissKorky you can not post urls in comments, but my website is on my channel page
patrickJMT 1 year ago
WHY ARE YU A LEFTY!?!??!!
snipermule6 1 year ago
you r superp , Great teacher ! I am learning a lot from your video. Thanks a lot!
jay2yosi 1 year ago
OMG IT IS SIMPLE!!!!!!!!
arual1969 1 year ago
thnks alotttt!!!!!!
MsRach77 1 year ago
Are you a maths professor?
xerxes0129 1 year ago
i know the interval from negative infinity to 0 of the second derivative is wrong, but isn't the graph right anyway? or am I missing a point?
SiksGameRuns 1 year ago
Man, the interval from - infinite to 0 of the 2nd derivative is wrong. You wrote it's positive man.
Hillumamu 1 year ago
@Hillumamu Yeah I see it too...
Santana2163 1 year ago
i don't know why i bother going to class. this is all i needed... much better than a "read your text book" session with my teacher
paperairplanes18 1 year ago
thank you so much
mynameishmay 1 year ago
why does the graph cross the horizontal asymptote
starwarsfreakdood 1 year ago
@starwarsfreakdood
cross over point probably
guylaroche5 1 year ago
The graph has a possibility to cross the HA, even tho its a HA
ClownDatWalk 1 year ago
@starwarsfreakdood A function can cross a horizontal asymptote as long as it approaches said horizontal value as it goes to infinity, it cannot, however, ever cross a vertical asymptote.
jazzysax102391 1 year ago
if im rich all my money will be given to you ;)
u have single handedly saved me from failing
tesla737 2 years ago 28
Thanks Pat, Ive been watching all of your videos, and they've helped alot...
lpbl2004 2 years ago 2
thanks a million patrick, these videos really helped
taginiho 2 years ago 6
wait. at 2:46 when you plug in the -1 into the double prime function isnt that supposed to be CD since its a negative over a positive?
xkrnaaax 2 years ago
nvm apparently everyone else caught it lol. my bad. great videos anyway!
xkrnaaax 2 years ago
is there a video for sketching and interpreting derivatives and the second derivative?
blacknikeboy 2 years ago
dont stop doing videos
julub 2 years ago 49
I thought the concavity from negative infinity to 0 was concave up? But the graph is concave down from negative infinity to 0. Not that it will ever reach 0 but I thought it would look different based on the information.
p0wnztv 2 years ago
hello, thank you for the video. I have a question, I am trying to obtain infexion points what should I do when in f I plug in the value that I obtained solving f '' and it results undefined? f(x)=f ' (X )= (-2x^2)+x+3) / (x+2) and f '' (x)= (-14(x+2)) / (x+2)^4 Does that mean that there are not inflexion points?
ver0mg 2 years ago
The graph seems correct to me either. You made a mistake back there but didn't draw it wrong at the end. I'd do the same sketch.
btw, thanks for doing that. Helped a lot.
13Nog 2 years ago
Question, u said there is a HA at 0, if that is the case there couldn't be any pts on the x-axis right? so how is it that we get an intercept at x=1? (I understand how we get that intercept, but it technically doesn't make sense).
manjula85 2 years ago
I know you made a mistake with the concave section but isn't that still the correct sketch?
Can you please do a video for curvilinear?
Kay0Bot 2 years ago 4
yeah its almost correct.. at the right corner it should be down down like on the x axis sort of thing..
but still thank you for this, your doing a great thing for this world dude!! =P and trust me my mom always says.. be nice to the nerds.. becasue one day youll be working for one.. =D
Kloosterman01 2 years ago
I think so too, he said concave down from (-infinity,0)
manjula85 2 years ago
That still is the correct sketch.
CaptainCarthex 2 years ago
thx alot man, u made it so easy to understand!! Short, simple and clear! Thx
Khmer22cambo 2 years ago
sorry i accidentally rated 4 stars..intended to click 5 ..
magic100172 2 years ago
dam thank god for ur videos.. my teacher is british and tries to be funny when he teaches... he says the same joke over and over again in class and the retard nerds laugh at it everytime...
term2121 2 years ago 2
i would probably laugh too
patrickJMT 2 years ago 15
im gonna take for second time calculus math 2 at college again :(
but with ur vids, and practicing a lot im gettin better :)so im going to past with high scores the next time :)
whynos666 2 years ago
Thank you so much Patrick...I now love curve sketching thanks to your video.
techlance 2 years ago
I loved this video and it saved my time of trying to understand this lecture by myself
Thanks a lot for this nice ,helpful ,and clear video
again thanks a lot
nbanour 2 years ago
I love you *3* very useful videos. I have a terrible prof this semester, he doesn't even know what he's doing, so this is a huuuuuuge help to clear things up :)
lildragonblue 2 years ago
wait i don't understand why the graph isn't correct still, what is incorrect?
illa2015 2 years ago
i think the graph has been corrected, this is what the graph should look like (the first part is concave down, decreasing) before he said it was concave up. Im pretty sure he made the correction already.
mi07ke 2 years ago
this is so nice of you to do for people. it really helps a lot. when im feeling too lazy to study myself and write out notes i can jut watch these!
robinvwhelan 2 years ago
dude just dont die! you saved my bacon, i didnt udnerstnad this stuff at all until i wtached this video,! thank you!
Kloosterman01 2 years ago
what does it mean when your criticals numbers from your first derivative are the same as the second derivative?i have a local minimum i found from the 1st der. but the same critical number showed up in the 2nd der.
jayz098 2 years ago
than you so much.... this was very helpful...
danny4213 2 years ago
I hate curve sketching. The process is so tedious.
initialg 3 years ago
could u do another sketch example...without the mistake :) please?
joeKing7 3 years ago 4
yes, plug it into the original. after all, we are trying to find inflection points on f(x); the first and second derivative just help to tell us where to 'look' on f(x)!
hope this helps!!
patrickJMT 3 years ago
So when you find the inflection number, you plug that into the ORIGINAL equation to find the y-coordinate of an inflection point, not the first derivative, right?
Thanks Patrick! [:
quynhho2002 3 years ago
amazing explanation.. u saved me from failing my test tommorow
Freedomboy006 3 years ago
good luck on your test!
patrickJMT 3 years ago
P-diddy, you're my savior for my calc test tomorrow thanks a lot!
JackEffenBauer 3 years ago
good luck on the test!
patrickJMT 3 years ago
this is making my calc class so much better
vash01000100 3 years ago 2
when you plugged in -1 for the concavity of the second derivative, shouldn't it be 2(-1-3)/1=2(-4)/1=concave down?
cookyhat155 3 years ago 3
yes, you are absolutely correct, thanks!
i will add annotations now thanking you!
thanks!
patrickJMT 3 years ago
Wonderful. Keep up the great work Patrick!!
leebh 3 years ago
i will do my best : )
patrickJMT 3 years ago
Great video Patrick! A nice clear explanation, what many students of Maths are after I believe :)
Draco488 3 years ago 2
howdy! i am trying to give you what i think is helpful, or what was helpful to me at least! glad that you all like it : )
patrickJMT 3 years ago
Great Explanation! Thanks for the help!
MATHGEEK1989 3 years ago