Added: 2 years ago
From: teachertubemath
Views: 12,682
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  • That was good, thank you :)

  • that mouse clicking is so annoying.

  • This was unbelievably helpful! Thank you so much for explaining this!

  • How can I solve exercises like

    1+2+3+...+n= Σ {above stands n; on the right i; at the bottom i=1}  = [n(n+1)]/2

  • yo helped me so much :) thank you man yua are genius :)

  • (5^n - 1) is divisible by four by assumption. We just need to know that 5^(n+1) -1 is divisible by 4 **IF we already know** that (5^n - 1) is divisible by four. So we assume the former, derive the latter, prove it for n=1, thus it is true for n=2, so since its true for n=2 its true for n=3 and so on

  • Where was the proof that (5^n - 1) was divisible by four? You only proved that it's true for 1 by substitutng 1 in the expression. You didn't prove it is true for any other 'n'.

    You broke the expression down nicely to a term containing two expressions ie (4x5^n) + (5^n - 1) the first term is clearly a multiple of four therefore poved...where is the ''proof'' for

    (5^n -1)? . It is true, of course but you haven't proved it. This sort of half proof is really sloppy.

  • thanks alottt :) :D :)

  • thank you!!

  • Very helpful.

  • Yeah great! Thanks, this was so hard to understand from the book. But now I got it :)

  • Thanks for this, I've been struggling with this for an entire week, now I get it!!! thanks

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